MySQL Where Clause错误

Question

我有以下声明

$result = mysql_query("SELECT * from rests ORDER BY name asc WHERE flag = '1' LIMIT 0 , 20");

我收到以下错误

Invalid query: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE flag = '1' LIMIT 0 , 20' at line 1

我不确定哪里出错了：（

Answer 1

$result = mysql_query("SELECT * from rests  WHERE flag = '1' ORDER BY name asc LIMIT 0 , 20");

Answer 2

ORDER BY子句之前不能有WHERE子句。

请参阅MySQL select syntax了解各种条款的正确顺序。

试试这个：

SELECT * from rests WHERE flag = '1' ORDER BY name asc LIMIT 0 , 20

另外，以升序排序是默认的，您可以放弃asc。

Answer 3

ORDER BY子句必须在WHERE子句之后。就是这样。

Answer 4

ORDER BY位于WHERE和LIMIT之后。

Answer 5

WHERE早于ORDER BY。