Question

我无法理解这个问题。始终返回故障。数据返回状态代码200，OnResponse不返回。

响应 D / OkHttp：＆lt; - 200 OK http://192.168.10.10/oauth/token（667ms）

此代码有什么问题？

App.java

public class App extends Application {

    private static ApiBackend api;
    private Retrofit retrofit;

    @Override
    public void onCreate() {
        super.onCreate();

        HttpLoggingInterceptor interceptor = new HttpLoggingInterceptor();
        interceptor.setLevel(HttpLoggingInterceptor.Level.BODY);
        OkHttpClient client = new OkHttpClient.Builder().addInterceptor(interceptor).build();


        retrofit = new Retrofit.Builder()
                .baseUrl("http://192.168.10.10/")
                .addConverterFactory(GsonConverterFactory.create())
               .client(client)
                .build();
        api = retrofit.create(ApiBackend.class);
    }

    public static ApiBackend getApi() {
        return api;
    }
}

接口

@FormUrlEncoded
@POST("oauth/token")
Call<List<AuthModel>> auth(
        @Field("username") String username,
        @Field("password") String password,
        @Field("grant_type") String grant_type,
        @Field("client_id") Integer client_id,
        @Field(

"client_secret") String client_secret
            );

AuthModel

public class AuthModel {
    List<AuthModel> TaskModel;
    @SerializedName("username")
    @Expose
    private String username;
    @SerializedName("password")
    @Expose
    private String password;
    @SerializedName("grant_type")
    @Expose
    private String grantType;
    @SerializedName("client_id")
    @Expose
    private Integer clientId;
    @SerializedName("client_secret")
    @Expose
    private String clientSecret;

    public String getUsername() {
        return username;
    }

    public void setUsername(String username) {
        this.username = username;
    }

    public String getPassword() {
        return password;
    }

    public void setPassword(String password) {
        this.password = password;
    }

    public String getGrantType() {
        return grantType;
    }

    public void setGrantType(String grantType) {
        this.grantType = grantType;
    }

    public Integer getClientId() {
        return clientId;
    }

    public void setClientId(Integer clientId) {
        this.clientId = clientId;
    }

    public String getClientSecret() {
        return clientSecret;
    }

    public void setClientSecret(String clientSecret) {
        this.clientSecret = clientSecret;
    }

}

MainActivity

        App.getApi().auth("admin@admin.com","admin123","password",2,"yl9s3UK74vSR1AxlCMhHqHO1AbTz9DzaXUVZyKpA").enqueue(new Callback<List<AuthModel>>() {
        @Override
        public void onResponse(Call<List<AuthModel>> call, Response<List<AuthModel>> response) {
            if (response.isSuccessful()) {
              Log.v(TAG,"ffff");
            } else {
                // error response, no access to resource?
            }
        }

        @Override
        public void onFailure(Call<List<AuthModel>> call, Throwable t) {
            Toast.makeText(MainActivity.this, "An error occurred during networking", Toast.LENGTH_SHORT).show();
        }
    });

Answer 1

问题在于您无法理解如何使用Retrofit库。

让我们看一下您在服务接口中声明的方法。

@FormUrlEncoded
@POST("oauth/token")
Call<List<AuthModel>> auth(
    @Field("username") String username,
    @Field("password") String password,
    @Field("grant_type") String grant_type,
    @Field("client_id") Integer client_id,
    @Field(

"client_secret") String client_secret
        );

行Call<List<AuthModel>>正在告诉改造api调用的响应是什么样的。你在这里要做的是期望看起来像你的AuthModel的东西，不仅仅是一个AuthModel列表。

您实际需要做的是

创建一个代表响应{ "token_type": "Bearer", "expires_in": 31536000}和
声明您的auth方法调用的预期响应，如Call<MyFunkyNewLoginResponseClass>

如果您在此之后仍然遇到问题，则需要另外提出问题。

Retrofit 2总是返回onFailure

1 个答案: