Question

我是angularJS的新手，我只是想问一下如何获得on-success属性的值，该属性将在成功的上传请求中具有JSON对象。 post-creator.template.html页面上存在“on-success”属性。

的index.html

<body>
    <div>
        <post-creator post-id="0"></post-creator>
    </div>
</body>

这是一个post-creator.template.html

<form role="form">
                <div class="form-group float-label-control">
                    <label>Title</label>
                    <input type="text" placeholder="Name" class="form-control" ng-model="model.post.title">
                </div>

                <div upload-button
                     url="/user_uploads"
                     on-success="onSuccess(response)"
                     on-error="onError(response)"
                     ng-model="onSuccess(response)"
                     >Upload</div>

                <div class="text-center">
                    <button type="button" class="btn btn-default" ng-click="model.save(model.post)">Save</button>
                </div>
            </form>

这是post-creator.component.js：

(function () {
    "use strict";

    var module = angular.module(__appName);

    function controller($http) {
        var model = this;
        model.post = null;

        model.save = function (post) {
           //get on-success value here
           //console.log(model.onSuccess);
        }
    }

    module.component("postCreator", {
        templateUrl: "components/post-creator/post-creator.template.html",
        bindings: {
            category: "<",
            postId: "<",
            subCategory: "<"
        },
        controllerAs: "model",
        controller: ["$http", controller]
    });
}());

Answer 1

您可以将$element注入您的控制器，并通过attributes将$element[0].attributes绑定到您的指令。

function controller($http, $element) {
  var attrs = $element[0].attributes;  
  // you own logic
}

AngularJS：获取控制器中的属性值

1 个答案: