Question

我有一个函数接收名为wchar_t*的{{1}}参数。

我希望调整somestring的大小以包含比传递更多的元素，b因为我想要复制比原始字符串更大的元素：

wchar_t* somestring

是否可以调整void a_function(wchar_t *somestring) { // I'd like the somestring could contain the following string: somestring = L"0123456789"; // this doesn't work bebause it's another pointer } int _tmain(int argc, _TCHAR* argv[]) { wchar_t *somestring = L"0123"; a_function(somestring); // now I'd like the somestring could have another string at the same somestring variable, it should have the following characters: "0123456789" }的大小以包含更多字符？

Answer 1

正如您所知，sumup只是更改了本地指针变量sum而对调用者没有任何影响。更改调用者的指针值需要传递指向此指针的指针：

int sum( int hello[], int size )
{
  int result = 0;
  for ( int i = 0; i < size; ++i )
    result += hello[i];
  return result;
}

int main( )
{
  ...
  int sumup = sum( hello, size );
  ...
}

请注意，通过覆盖指针，您将松开对字符串文字public class DBConnectorFactory { private static volatile DBConnector dBConnector = null; private static AtomicReference<DBConnector> atomicReference = new AtomicReference<>(); private DBConnectorFactory() {} public static DBConnector getDBConnector(DBConfig dBConfig) { if(dBConnector == null) { if(atomicReference.compareAndSet(null,new DBConnector(dBConfig))) dBConnector = atomicReference.get(); return atomicReference.get(); } else return dBConnector; }的引用。请进一步注意，数据类型现在为pkg-config --cflags gtk+3.0，否则不应分配字符串文字（不允许修改字符串文字的内容）。

是否可以更改wchar_t *的内容？

1 个答案: