我有一个函数接收名为wchar_t*
的{{1}}参数。
我希望调整somestring
的大小以包含比传递更多的元素,b因为我想要复制比原始字符串更大的元素:
wchar_t* somestring
是否可以调整void a_function(wchar_t *somestring) {
// I'd like the somestring could contain the following string:
somestring = L"0123456789"; // this doesn't work bebause it's another pointer
}
int _tmain(int argc, _TCHAR* argv[])
{
wchar_t *somestring = L"0123";
a_function(somestring);
// now I'd like the somestring could have another string at the same somestring variable, it should have the following characters: "0123456789"
}
的大小以包含更多字符?
答案 0 :(得分:2)
正如您所知,sumup
只是更改了本地指针变量sum
而对调用者没有任何影响。更改调用者的指针值需要传递指向此指针的指针:
int sum( int hello[], int size )
{
int result = 0;
for ( int i = 0; i < size; ++i )
result += hello[i];
return result;
}
int main( )
{
...
int sumup = sum( hello, size );
...
}
请注意,通过覆盖指针,您将松开对字符串文字public class DBConnectorFactory
{
private static volatile DBConnector dBConnector = null;
private static AtomicReference<DBConnector> atomicReference = new AtomicReference<>();
private DBConnectorFactory()
{}
public static DBConnector getDBConnector(DBConfig dBConfig)
{
if(dBConnector == null)
{
if(atomicReference.compareAndSet(null,new DBConnector(dBConfig)))
dBConnector = atomicReference.get();
return atomicReference.get();
}
else
return dBConnector;
}
的引用。
请进一步注意,数据类型现在为pkg-config --cflags gtk+3.0
,否则不应分配字符串文字(不允许修改字符串文字的内容)。