Question

我的作业计划几乎完成了所有内容。最后一个功能是让程序显示在输入中找到的特定元音。例如：

Please enter a word: look
The vowels in your word are 
o
o
there were 2 vowels
I'm terribly sorry if I missed any 'y's.

代码：

def main():
    vowels = ["a","e","i","o","u"]
    count = 0
    string = input(str("please enter a word:"))
    for i in string:
        if i in vowels:
            count += 1

    print("The vowels in your word are:")

    print("There were",count,"vowels")
    print("Sorry if I missed any 'y's")

if __name__ == "__main__":
    main()

Answer 1

你所缺少的就是在找到它们时保留一串元音。这很像计算元音。从＆＃34;基值开始＃34;一个字符串，空字符串。每次找到元音时，将（连接它）添加到字符串中。例如：

vowels_found = ""
for i in string:
    if i in vowels:
        vowels_found += i
print(vowels_found)
print(len(vowels_found))

在此之后，在您计划的位置打印vowels_found。如果你想要它们在单独的行上，就像你发布的样本一样，那么在循环中打印每个，并且根本不使用vowels_found。

在python中有更高级，更直接的方法：你可以在一个语句中包含过滤，这个例程基本上是两行：一个用于收集元音，另一个用于计数和打印它们。在课堂上稍后担心那些......但如果有人发布这些解决方案，请注意。： - ）

Answer 2

您可以在if内添加打印声明。这样，当找到元音时，它将以您在问题中显示的方式打印。

请注意，您需要将print("The vowels in your word are:")移至if之前，以便在元音之前打印。

例如

def main():
    vowels = ["a","e","i","o","u"]
    count = 0
    string = input(str("please enter a word:"))
    print("The vowels in your word are:") #puts text before the vowels printed in `if`
    for i in string:
        if i in vowels:
            count += 1
            print (i) #prints the vowel if it is found



    print("There were",count,"vowels")
    print("Sorry if I missed any 'y's")

if __name__ == "__main__":
main()

如何显示单词中的特定元音

2 个答案: