Question

我正在访问某个网站，我想上传一个文件。

我在python中编写了代码：

import requests

url = 'http://example.com'
files = {'file': open('1.jpg', 'rb')}
r = requests.post(url, files=files)
print(r.content)

但似乎没有上传文件，页面与初始页面相同。

我想知道如何上传文件。

该页面的源代码：

<html><head><meta charset="utf-8" /></head>

<body>
<br><br>
Upload<br><br>
<form action="upload.php" method="post"
enctype="multipart/form-data">
<label for="file">Filename:</label>
<input type="hidden" name="dir" value="/uploads/" />
<input type="file" name="file" id="file" /> 
<br />
<input type="submit" name="submit" value="Submit" />
</form>

</body>
</html>

Answer 1

几点：

请务必将您的请求提交到正确的网址（表单'action'）
使用files参数提交其他表单字段（'dir'，'submit'）
在import requests url = 'http://example.com' + '/upload.php' data = {'dir':'/uploads/', 'submit':'Submit'} files = {'file':('1.jpg', open('1.jpg', 'rb'))} r = requests.post(url, data=data, files=files) print(r.content)中包含文件的名称（这是可选的）

代码：

namespace Detailing
{
public partial class MainForm : Form
{
    public void hidePanels()
    {
        welcomePanel.Width = 0;
        homePanel.Width = 0;
        historyPanel.Width = 0;
        savePanel.Width = 0;
    }
    public MainForm()
    {
        InitializeComponent();
        Load += new EventHandler(MainForm_Load);
    }
    private void MainForm_Load(object sender, EventArgs e)
    {
        hidePanels();
        welcomePanel.Width = 1306;
    }

    private void homeButton_Click(object sender, EventArgs e)
    {
        hidePanels();
        homePanel.Width = 1306;
    }
}
}

Answer 2

首先，定义上传目录的路径，如

app.config['UPLOAD_FOLDER'] = 'uploads/'

然后定义允许上传的文件扩展名，

app.config['ALLOWED_EXTENSIONS'] = set(['txt', 'pdf', 'png', 'jpg', 'jpeg', 'gif'])

现在假设您调用函数来处理上传文件，那么您必须编写类似这样的代码，

# Route that will process the file upload
@app.route('/upload', methods=['POST'])
def upload():
    # Get the name of the uploaded file
    file = request.files['file']

    # Check if the file is one of the allowed types/extensions
    if file and allowed_file(file.filename):
        # Make the filename safe, remove unsupported chars
        filename = secure_filename(file.filename)

        # Move the file form the temporal folder to
        # the upload folder we setup
        file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename))

        # Redirect the user to the uploaded_file route, which
        # will basicaly show on the browser the uploaded file
        return redirect(url_for('YOUR REDIRECT FUNCTION NAME',filename=filename))

这样您就可以上传文件并将其存储在您找到的文件夹中。

我希望这会对你有所帮助。

感谢。

python请求上传文件

2 个答案: