我遇到了一个我无法弄清楚的问题。我根据this示例编写了一个简单的自定义IME键盘。
它基本上有两个自定义键盘,一个用于字母,一个用于数字。他们使用不同的布局。
但是,当我添加两个EditText
控件时,一个用于文本,一个用于数字,键盘不会刷新到它所属的类型。我的意思是,如果我首先选择带有EditText
的{{1}},则会出现QWERTY键盘布局。但是当我用inputType="text"
选择第二个EditText
时,QWERTY键盘再次出现。但是,它应该为连接到代码中的数字加载不同的布局。
换句话说,这是测试活动布局:
现在,如果我选择“文本”字段,QWERTY键盘将显示如下:
但是,如果我选择“数字”字段,QWERTY键盘仍会显示错误。
预期的行为是这个键盘出现。
以下是CustomIME的代码,我尝试在视图上使用inputType="number"
,在postInvalidate()
期间预加载所有布局但没有任何效果。它永远不会正确切换到数字的布局
onInitializeInterface()
布局:
custom_ime_keyboard.xml:
public class CustomIME extends InputMethodService
implements KeyboardView.OnKeyboardActionListener {
public static final String CUSTOM_IME = "CUSTOM_IME";
private KeyboardView mKeyboardView;
private Keyboard mKeyboardCurrent;
private KeyboardType mKeyboardTypeCurrent = KeyboardType.QWERTY_LETTERS;
private boolean mCAPs = false;
enum KeyboardType {
QWERTY_LETTERS,
NUMBERS
}
@Override
public View onCreateInputView() {
loadCurrentKeyboard();
mKeyboardView = (KeyboardView) getLayoutInflater().inflate(R.layout.custom_ime_keyboard, null);
mKeyboardView.setBackgroundResource(R.drawable.btn_gradient);
mKeyboardView.setOnKeyboardActionListener(this);
if (mKeyboardCurrent != null) {
mKeyboardView.setKeyboard(mKeyboardCurrent);
}
return mKeyboardView;
}
@Override
public void onInitializeInterface() {
// tried loading everything here but did not make a difference
}
private void loadCurrentKeyboard() {
if (mKeyboardTypeCurrent == KeyboardType.QWERTY_LETTERS) {
mKeyboardCurrent = new Keyboard(getApplicationContext(), R.xml.custom_ime_qwerty);
} else if (mKeyboardTypeCurrent == KeyboardType.NUMBERS) {
mKeyboardCurrent = new Keyboard(getApplicationContext(), R.xml.custom_ime_number);
} else {
Log.e(CUSTOM_IME, "Invalid keyboard type");
}
}
@Override
public void onStartInput(EditorInfo attribute, boolean restarting) {
super.onStartInput(attribute, restarting);
switch (attribute.inputType & InputType.TYPE_MASK_CLASS) {
case InputType.TYPE_CLASS_NUMBER:
boolean signed = (attribute.inputType & InputType.TYPE_NUMBER_FLAG_SIGNED) != 0;
boolean decimal = (attribute.inputType & InputType.TYPE_NUMBER_FLAG_DECIMAL) != 0;
// set default
mKeyboardTypeCurrent = KeyboardType.QWERTY_LETTERS;
if (!signed && !decimal) {
mKeyboardTypeCurrent = KeyboardType.NUMBERS;
}
break;
case InputType.TYPE_CLASS_TEXT:
default:
mKeyboardTypeCurrent = KeyboardType.QWERTY_LETTERS;
}
// This did not make a difference
if (mKeyboardView != null) {
mKeyboardView.postInvalidate();
}
}
@Override
public void onKey(int primaryCode, int[] keyCodes) {
InputConnection inputConnection = getCurrentInputConnection();
switch (primaryCode) {
default:
char asciiCode = (char) primaryCode;
if (Character.isLetter(asciiCode) && mCAPs) {
asciiCode = Character.toUpperCase(asciiCode);
}
inputConnection.commitText(String.valueOf(asciiCode), 1);
}
}
}
activity_main.xml中
<?xml version="1.0" encoding="UTF-8"?>
<android.inputmethodservice.KeyboardView xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@+id/custom_ime_keyboard_id1"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:layout_alignParentBottom="true"
android:keyPreviewLayout="@layout/custom_ime_preview" />
最后是键盘布局( custom_ime_qwerty.xml 和 custom_ime_number.xml )。
<LinearLayout
android:id="@+id/layout1"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_alignParentTop="true"
android:layout_centerHorizontal="true"
android:layout_margin="10dp"
android:orientation="horizontal">
<EditText
android:id="@+id/edit1"
android:layout_width="100dp"
android:layout_height="60dp"
android:inputType="text"
android:hint="Text"
android:padding="10dp"
android:textSize="12sp" />
<EditText
android:id="@+id/edit2"
android:layout_width="100dp"
android:layout_height="60dp"
android:hint="Number"
android:inputType="number"
android:padding="10dp"
android:textSize="12sp" />
</LinearLayout>
答案 0 :(得分:10)
我认为onStartInputView()
是您需要获得的回调:
在显示输入视图并在新编辑器上开始输入时调用。这将始终在 onStartInput(EditorInfo,boolean)之后调用,允许您在此处进行常规设置,并在此处进行特定于视图的设置。您可以保证在调用此函数之前调用 onCreateInputView()。
因此,您可以了解要在onStartInput()
中显示的确切输入类型,但切换到此新键盘类型的实际位置应为onStartInputView()
。
了解示例SoftKeyboard
应用程序如何处理该功能。
@Override public void onStartInput(EditorInfo attribute, boolean restarting) {
super.onStartInput(attribute, restarting);
...
// We are now going to initialize our state based on the type of
// text being edited.
switch (attribute.inputType & InputType.TYPE_MASK_CLASS) {
case InputType.TYPE_CLASS_NUMBER:
case InputType.TYPE_CLASS_DATETIME:
mCurKeyboard = mSymbolsKeyboard;
break;
case InputType.TYPE_CLASS_PHONE:
mCurKeyboard = mSymbolsKeyboard;
break;
case InputType.TYPE_CLASS_TEXT:
mCurKeyboard = mQwertyKeyboard;
...
break;
default:
// For all unknown input types, default to the alphabetic
// keyboard with no special features.
mCurKeyboard = mQwertyKeyboard;
}
}
@Override public void onStartInputView(EditorInfo attribute, boolean restarting) {
super.onStartInputView(attribute, restarting);
// Apply the selected keyboard to the input view.
setLatinKeyboard(mCurKeyboard);
...
}
private void setLatinKeyboard(LatinKeyboard nextKeyboard) {
final boolean shouldSupportLanguageSwitchKey =
mInputMethodManager.shouldOfferSwitchingToNextInputMethod(getToken());
nextKeyboard.setLanguageSwitchKeyVisibility(shouldSupportLanguageSwitchKey);
mInputView.setKeyboard(nextKeyboard);
}