Question

我尝试用其他东西将包装成括号的东西用字符串替换。我得到了非常奇怪的结果。

HTML / JS

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var string = document.getElementById('test').innerHTML;
var replace = string.replace(/[prefix]/g, "replaced");
console.log(replace); // Look in developer tools console

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<div id="test">A little [prefix] test</div>

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原始字符串

一点[前缀]测试

预期（我希望的）

一点点替换测试

结果

lreplacedttlreplaced [replacementreplacedreplacedreplacedreplacedreplacedreplaced] treplacedst

我还想替换多个匹配项，这就是我使用/g的原因。

Answer 1

你必须逃避CREATE OR REPLACE FUNCTION state_group_count_and_sum( state map<timestamp, frozen<tuple<bigint,double>>>, timestamp timestamp, value double ) CALLED ON NULL INPUT RETURNS map<timestamp, frozen<tuple<bigint,double>>> LANGUAGE java AS ' Date date = (Date) timestamp; Calendar cal = Calendar.getInstance(); // locale-specific cal.setTime(date); cal.set(Calendar.HOUR_OF_DAY, 0); cal.set(Calendar.MINUTE, 0); cal.set(Calendar.SECOND, 0); cal.set(Calendar.MILLISECOND, 0); date = cal.getTime(); TupleValue tupleValue = state.get(date); Long count = (Long) tupleValue.getLong(0); if (count == null) count = 1L; else count = count + 1L; Double sum = (Double) tupleValue.getDouble(1); if (sum == null) sum = value; else sum = sum + value; //if (tupleValue == null) ? tupleValue.setLong(0, count); tupleValue.setDouble(1, sum); state.put(date, tupleValue); return state; ' ; CREATE OR REPLACE AGGREGATE group_count_and_sum(timestamp, double) SFUNC state_group_count_and_sum STYPE map<timestamp, frozen<tuple<bigint,double>>> INITCOND {};。

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var string = document.getElementById('test').innerHTML;
var replace = string.replace(/\[prefix]/g, "Replaced");
console.log(replace); // Look in developer tools console

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Answer 2

你应该使用这个

string.replace(/\[prefix]/g, "Replaced");

Answer 3

你需要以正则表达式模式转义__getitem__。方括号在正则表达式中起重要作用。查看How can I put \[\] (square brackets) in RegExp javascript?

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[]

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var string = document.getElementById('test').innerHTML;
var replace = string.replace(/\[prefix\]/g, "replaced");
console.log(replace); // Look in developer tools console

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Javascript字符串用括号替换短标签

3 个答案: