程序工作正常并执行所有选项，但在第3和第4选项中，在第3次搜索学生时，程序不会超出数据输入部分，而在第4次搜索数据并打印时，它在int数据类型的变量中给出了垃圾值，而不显示字符串或char类型变量。任何帮助将非常感激。编辑：抱歉给您带来不便，我现在将功能从主代码中分离出来。希望现在更容易理解。
#include<iostream>
#include<string>
using namespace std;
int ncr;
int me,n=0,u,y,l;
char opt1,opt2,opt3,opt4;
struct student
{
string Name;
int DoB;
int Age;
string Address;
string Course[5];
char grade[5];
};
void add();
void remove();
void update();
void search();
int main()
{ int opt;
student s[n];
while(1)
{
cout<<" select what you want to do \n\n 1. Add new record \n2. Remove record\n3. Update Record\n4. Search for particular student\n" ;
cin>>opt;
if(opt==1)
{add();}
else if(opt==2)
{remove();}
else if(opt==3)
{update();}
else if(opt==4)
{search();}
}
}
void add(){
n++;
student s[n];
do
{ cout<<"enter name of student ";
cin>>s[n-1].Name;
cout<<"enter DoB of student ";
cin>>s[n-1].DoB;
cout<<"enter age of student ";
cin>>s[n-1].Age;
cout<<"enter address of student ";
cin>>s[n-1].Address;
cout<<"enter courses and grades (max 5) \n";
for(int x=0;x<5;x++){
cout<<"course:";
cin>>s[n-1].Course[x];
cout<<"grade:";
cin>> s[n-1].grade[x];}
cout<<"Roll No. : "<<n<<"\nName :"<<s[n-1].Name<<"\nDoB :"<<s[n-1].DoB<<"\nAge :"<<s[n-1].Age<<"\nAddress :"<<s[n-1].Address;
for(int x=0;x<5;x++){
cout<<"\n"<<s[n-1].Course[x];
cout<<" grade : "<< s[n-1].grade[x]<<"\n";}
cout<<"repeat for another student 'y' or 'n' ?";
cin>>opt1;
}
while(opt1=='y'|| opt1=='Y');
}
void remove(){student s[n];
do
{
cout<<"enter student roll no to remove data";cin>>l;
for(int i=l;i<n;i++)
{ s[l-1].Name=s[l].Name;
s[l-1].DoB= s[l].DoB;
s[l-1].Age=s[l].Age;
s[l-1].Address=s[l].Address;
for(int j=0;j<5;j++){
s[l-1].Course[j]=s[l].Course[j];
s[l-1].grade[j]=s[l].grade[j];}
}
cout<<"Record Removed\n";
n--;
cout<<"repeat ? 'y' or 'n' ";
cin>>opt2;
}
while(opt2 == 'y' || opt2 == 'Y');}
void update(){
student s[n];
do
{
cout<<"enter the roll no of student you want to update data";
cin>>u;
cout<<"Roll No. : "<<u;
cout<<"\nName : ";
cout<<s[u-1].Name;
cout<<"\nDoB : ";
cout<<s[u-1].DoB;
cout<<"\nAge : ";
cout<<s[u-1].Age;
cout<<"\nAddress :";
cout<<s[u-1].Address;
cout<<"\nCourses and Grades\n";
for(int r=0;r<5;r++)
{
cout<<s[u-1].Course[r];
cout<<"\t"<< s[u-1].grade[r]<<endl;
}
cout<<"enter name of student ";
cin>>s[u-1].Name;
cout<<"enter DoB of student ";
cin>>s[u-1].DoB;
cout<<"enter age of student ";
cin>>s[u-1].Age;
cout<<"enter address of student ";
cin>>s[u-1].Address;
cout<<"enter courses and grades (max 5) \n";
for(int x=0;x<5;x++){
cout<<"course:";
cin>>s[u-1].Course[x];
cout<<"grade:";
cin>> s[u-1].grade[x];}
cout<<"Roll No. : "<<u;
cout<<"\nName : ";
cout<<s[u-1].Name;
cout<<"\nDoB : ";
cout<<s[u-1].DoB;
cout<<"\nAge : ";
cout<<s[u-1].Age;
cout<<"\nAddress :";
cout<<s[u-1].Address;
cout<<"\nCourses and Grades\n";
for(int r=0;r<5;r++)
{ cout<<s[u-1].Course[r];
cout<<"\t"<< s[u-1].grade[r]<<endl; }
cout<<"repeat ? 'y' or 'n' ";
cin>>opt3;
}
while(opt3 == 'y' || opt3 == 'Y');
}
void search(){
student s[n];
do
{
cout<<"enter the roll no of student you want to search data of";
cin>>y;
cout<<"Roll No. : "<<n<<"\nName :"<<s[y-1].Name<<"\nDoB :"<<s[y-1].DoB<<"\nAge :"<<s[y-1].Age<<"\nAddress :"<<s[y-1].Address<<"\nCourses and Grades\n";
for(int r=0;r<5;r++)
{
cout<<s[y-1].Course[r];
cout<<"\t"<< s[y-1].grade[r]<<endl;
}
cout<<"repeat ? 'y' or 'n' ";
cin>>opt4;
}
while(opt4 == 'y' || opt4 == 'Y');}
答案 0 :(得分：1)
这应该看起来更像是一个供人类阅读的代码：）
#include<iostream>
#include<string>
using namespace std;
int ncr;
int me,n=0,u,y,l;
char opt1,opt2,opt3,opt4;
struct student
{
string Name;
int DoB;
int Age;
string Address;
string Course[5];
char grade[5];
};
void add();
void remove();
void update();
void search();
int main()
{
int opt;
student s[n];
while(1)
{
cout << " select what you want to do \n\n 1. Add new record \n2. Remove record\n3. Update Record\n4. Search for particular student\n" ;
cin >> opt;
if(opt==1)
{
add();
}
else if(opt==2)
{
remove();
}
else if(opt==3)
{
update();
}
else if(opt==4)
{
search();
}
}
}
void add()
{
n++;
student s[n];
do
{
cout << "enter name of student ";
cin >> s[n-1].Name;
cout << "enter DoB of student ";
cin >> s[n-1].DoB;
cout << "enter age of student ";
cin >> s[n-1].Age;
cout << "enter address of student ";
cin >> s[n-1].Address;
cout << "enter courses and grades (max 5) \n";
for(int x=0;x<5;x++)
{
cout<<"course:";
cin>>s[n-1].Course[x];
cout<<"grade:";
cin>> s[n-1].grade[x];
}
cout << "Roll No. : " << n << "\nName :" << s[n-1].Name << "\nDoB :" << s[n-1].DoB << "\nAge :" << s[n-1].Age << "\nAddress :" << s[n-1].Address;
for( int x = 0; x < 5; x++ )
{
cout << "\n"<<s[n-1].Course[x];
cout << " grade : "<< s[n-1].grade[x]<<"\n";}
cout << "repeat for another student 'y' or 'n' ?";
cin >> opt1;
}
while(opt1=='y'|| opt1=='Y');
}
void remove()
{
student s[n];
do
{
cout << "enter student roll no to remove data";
cin >> l;
for( int i=l; i < n; i++ )
{
s[l-1].Name=s[l].Name;
s[l-1].DoB= s[l].DoB;
s[l-1].Age=s[l].Age;
s[l-1].Address=s[l].Address;
for(int j=0;j<5;j++)
{
s[l-1].Course[j]=s[l].Course[j];
s[l-1].grade[j]=s[l].grade[j];
}
}
cout<<"Record Removed\n";
n--;
cout << "repeat ? 'y' or 'n' ";
cin >> opt2;
}
while(opt2 == 'y' || opt2 == 'Y');
}
void update()
{
student s[n];
do
{
cout << "enter the roll no of student you want to update data";
cin >> u;
cout << "Roll No. : " << u;
cout << "\nName : ";
cout << s[u-1].Name;
cout << "\nDoB : ";
cout << s[u-1].DoB;
cout << "\nAge : ";
cout << s[u-1].Age;
cout << "\nAddress :";
cout << s[u-1].Address;
cout << "\nCourses and Grades\n";
for( int r=0; r < 5; r++ )
{
cout << s[u-1].Course[r];
cout << "\t"<< s[u-1].grade[r] << endl;
}
cout << "enter name of student ";
cin >> s[u-1].Name;
cout << "enter DoB of student ";
cin >> s[u-1].DoB;
cout << "enter age of student ";
cin >> s[u-1].Age;
cout << "enter address of student ";
cin >> s[u-1].Address;
cout << "enter courses and grades (max 5) \n";
for(int x=0; x < 5; x++ )
{
cout<<"course:";
cin>>s[u-1].Course[x];
cout<<"grade:";
cin>> s[u-1].grade[x];
}
cout << "Roll No. : " << u;
cout << "\nName : ";
cout << s[u-1].Name;
cout << "\nDoB : ";
cout << s[u-1].DoB;
cout << "\nAge : ";
cout << s[u-1].Age;
cout << "\nAddress :";
cout << s[u-1].Address;
cout << "\nCourses and Grades\n";
for( int r = 0; r < 5; r++)
{
cout << s[u-1].Course[r];
cout << "\t"<< s[u-1].grade[r]<<endl;
}
cout << "repeat ? 'y' or 'n' ";
cin >> opt3;
}
while(opt3 == 'y' || opt3 == 'Y');
}
void search()
{
student s[n];
do
{
cout << "enter the roll no of student you want to search data of";
cin >> y;
cout << "Roll No. : " << n << "\nName :" << s[y-1].Name << "\nDoB :" << s[y-1].DoB << "\nAge :" << s[y-1].Age << "\nAddress :" << s[y-1].Address << "\nCourses and Grades\n";
for( int r=0; r < 5; r++ )
{
cout << s[y-1].Course[r];
cout << "\t" << s[y-1].grade[r]<<endl;
}
cout << "repeat ? 'y' or 'n' ";
cin >> opt4;
}
while( opt4 == 'y' || opt4 == 'Y' );
}
您遇到的问题在于您的计划范围。 在main（）函数中，您声明了一个数组，可能应该保存所有记录。但是对于每个选项（函数添加/删除/更新/搜索），您都声明一个新选项。这些阵列对这些功能来说是本地，并且正在被遗忘＆＃34;功能完成后。 为了解决这个问题，你必须将原始数组（main（）中的数组）传递给那些函数。
下一个更严重的问题是，您无法在运行时更改数组的大小！您在第3个选项中访问的元素是一些内存中的随机字节，这可能会造成很多麻烦。
用例如创建一个数组100个字段（student s[100];），甚至更好地尝试使用std::vector，其大小可以根据记录数量进行调整。
第三件事，请记住格式化代码非常重要。希望这只是一个复制粘贴问题，使您的代码看起来不可读，但如果情况并非如此，那么请尝试更改。格式良好的代码更容易理解，并使您更容易调试它。