Question

我使用下面的代码显示目录中的所有jpg。

$dirname = "var/www/media/";
$images = glob($dirname."*.jpg");

foreach($images as $image) {
    echo '<img src="'.$image.'" /><br />';
}

在同一目录中，我有同名电影。例如：

ls var/www/media
Aliens.mpg
Aliens.jpg
Simsons.avi
Simsons.jpg

我需要每个jpg图像都可以点击，链接到相应的视频文件。

这样做有简单的方法吗？

Answer 1

你走了！

注意
1）确保文件名相同。
2）您可以在变量$vidExts和<?php $files = glob("media/*.*"); $vid = NULL; $imgExts = array("gif", "jpg", "jpeg", "png", "tiff", "tif"); $vidExts = array("mp4", "mpg", "avi", "mk4", "ogg", "3gp"); for ($i=0; $i<count($files); $i++) { $image = $files[$i]; $urlExt = pathinfo($files[$i], PATHINFO_EXTENSION); if (in_array($urlExt, $imgExts)) { for ($j=0; $j<count($files); $j++) { $urlExt2 = pathinfo($files[$j], PATHINFO_EXTENSION); if (in_array($urlExt2, $vidExts)) { if (strcmp($urlExt, $urlExt2) == 0) { $vid=$files[$j]; } } } echo '<a href="'.$vid .'"><img src="'.$image .'" />'."<br /></a>"; } }中添加更多ext文件。

<?php
$x=1;   // initially giving value for x=1 
$files = glob("media/*.*");
$vid=NULL;
$vidf=$files;   //making copy of files array





$imgExts = array("gif", "jpg", "jpeg", "png", "tiff", "tif");
$vidExts = array("mp4", "mpg", "avi", "mk4", "ogg", "3gp");

for ($i=0; $i<count($files); $i++) {
    $image = $files[$i];


$urlExt = pathinfo($files[$i], PATHINFO_EXTENSION);

    if(in_array($urlExt,$imgExts )){
        for($j=0; $j<count($files); $j++){
          $urlExt2 = pathinfo($files[$j], PATHINFO_EXTENSION);
            if(in_array($urlExt2,$vidExts )){

                if(strcmp(pathinfo($files[$i], PATHINFO_FILENAME),pathinfo($files[$j], PATHINFO_FILENAME))==0){
                $vid=$files[$j];
                $x=0;   // put the value of x=0 if video for that image found!


        unset($vidf[array_search($vid , $vidf)]); // search & delete video from array with have images


                }
            }
        }





        if($x==0)
        echo '<a href="'.$vid .'"><img src="'.$image .'" />'."<br /></a>";

        else if($x==1){     //check if image have the video
        echo 'Video for Image <b>', pathinfo($image , PATHINFO_FILENAME),'.',pathinfo($image , PATHINFO_EXTENSION),  ' </b>Not Found!<br>';
        $x=0;}
}
}

    foreach ($vidf as $vidf) {    // show let out videos who's images not found

        $urlExt2 = pathinfo($vidf, PATHINFO_EXTENSION);
            if(in_array($urlExt2,$vidExts )){
    echo "Image of the Video <b> ",pathinfo($vidf , PATHINFO_FILENAME),'.', pathinfo($vidf , PATHINFO_EXTENSION),'</b> Not found!' ;
    echo '<br>';
            }
} 


?>

<强>更新

如果找不到任何文件（例如，如果找不到视频图像，反之亦然），则会显示错误

JavaPairReceiverInputDStream<String, String> messages =
            KafkaUtils.createStream(jssc, zkQuorum, groupId, topicMap);

JavaDStream<String> lines = messages.map(Tuple2::_2);
JavaDStream<String> words = lines.flatMap(x -> Arrays.asList(SPACE.split(x)).iterator());
JavaPairDStream<String, Integer> wordCounts = words.mapToPair(s -> new Tuple2<>(s, 1))
            .reduceByKey((i1, i2) -> i1 + i2);

显示目录中的图像并链接到同名视频

1 个答案: