我有接收SearchProfilesModel对象的控制器。它由SearchProfiles数组和基类中的几个属性组成。 方法:
[HttpGet]
[ResponseType(typeof(List<UserSearchResult>))]
[Route("SearchWithParams")]
public async Task<HttpResponseMessage>
SearchWithParams([FromUri] SearchProfilesModel model)
{
// Some logic
return Request.CreateResponse(HttpStatusCode.OK, result);
}
模特课:
public class SearchProfilesModel : LoginRequiredModel
{
[Required]
[JsonProperty("search_profiles")]
public List<SearchProfileViewModel> ProfilesList { get; set; }
}
列出项目类:
public class SearchProfileViewModel
{
[JsonProperty("name")]
public string Name { get; set; }
[JsonProperty("surname")]
public string Surname { get; set; }
[JsonProperty("facebook_id")]
public string FacebookId { get; set; }
[JsonProperty("email")]
public string Email { get; set; }
}
我使用Swagger ui(swashbuckle lib)来测试我的控制器,但是当它为这个方法生成帮助页面时,它显示如下: Help page
我的问题是 - 我能以某种方式在参数中显示列表项的结构(来自SearchProfileViewModel)吗?如果我能 - 怎么样? 附: - 对不起我的英语,这不是我的母语。
答案 0 :(得分:0)
你的对象的结构在生成的doc中,看看我的: http://swashbuckletest.azurewebsites.net/swagger/docs/v1
{
"swagger": "2.0",
"info": {...},
"host": "swashbuckletest.azurewebsites.net",
"schemes": [...],
"paths": {...},
"definitions": {
"Data": {
"type": "object",
"properties": {
"integ": {
"format": "int32",
"type": "integer",
"example": 123
},
"doub": {
"format": "double",
"type": "number",
"example": 9858.216
},
"boolea": {
"type": "boolean"
},
"guid": {
"format": "uuid",
"type": "string",
"example": "f5849915-43c8-434c-92a7-7383d1acb631"
},
"date": {
"format": "date-time",
"type": "string"
}
}
},
...