在matplotlib中对齐圆圈中的标签

时间:2017-05-11 15:30:46

标签: python matplotlib

我在pyplot中遇到文本对齐方面的困难。我试图在圆形树状图中注释以圆形方式排列的点,因此重要的是标签指向远离点并保持直角。这是我到目前为止的相关部分。 dots in a circle

水平标签就像一个魅力,但垂直标签显然是关闭的。似乎horizontalalignment / verticalalignment应用于原始坐标和边界框。是否有任何选项/方式来正确对齐标签而不执行一些疯狂的特技,比如找出文本高度并相应地移动标签。我想知道用极坐标覆盖第二个绘图/轴并将文本放在上面是否有意义,但我不确定这是否会引导我到任何地方。或者说我错过了一些非常明显的东西......

这是一个最小的工作示例:

import matplotlib.pyplot as plt

(fig, ax) = plt.subplots(figsize = (4,4))

def kex(N):
    alpha = 360. / N
    coordX = []
    coordY = []
    alphas = []
    for i in range(0,N):
        alpha_loop = alpha * i
        coordX.append( math.cos(math.radians(alpha_loop)) )
        coordY.append( math.sin(math.radians(alpha * i)) )
        alphas.append(alpha_loop)
    return [coordX, coordY, alphas]

N = 10
points = kex(N)
ax.scatter(points[0], points[1])
for i in range(0,N):
    x = points[0][i]
    y = points[1][i]
    a = points[2][i]
    if x > 0:
        ax.text(x + x * 0.1, y + y * 0.1, "AAA", rotation = a,
                    bbox=dict(facecolor = "none", edgecolor ="red"))
    else:
        ax.text(x + x * 0.1, y + y * 0.1, "AAA", rotation = a - 180,
                    bbox=dict(facecolor = "none", edgecolor ="red"), ha = "right")

ax.axis("off")

plt.show()

感谢任何帮助!

1 个答案:

答案 0 :(得分:2)

您可以将文本偏移到足以使其与点重叠。然后,我们的想法是对文本进行居中对齐(ha="center", va="center"),这样就可以坐在图形中点和它注释点之间的扩展(虚拟)线上。

import matplotlib.pyplot as plt
import numpy as np

(fig, ax) = plt.subplots(figsize = (4,4))

def kex(N):
    alpha=2*np.pi/N
    alphas = alpha*np.arange(N)
    coordX = np.cos(alphas)
    coordY = np.sin(alphas)

    return np.c_[coordX, coordY, alphas]

N = 10
r = 1.2
points = kex(N)
ax.scatter(points[:,0], points[:,1])

for i in range(0,N):
    a = points[i,2] 
    x,y = (r*np.cos(a), r*np.sin(a))
    if points[i,0] < 0: a = a - np.pi
    ax.text(x,y, "AAA", rotation = np.rad2deg(a), ha="center", va="center",
                    bbox=dict(facecolor = "none", edgecolor ="red"))

ax.axis("off")

plt.show()

enter image description here