Question

我已经远距离搜索但找不到我的任务的解决方案。我需要能够从输入中获取单词的位置，然后将其和单词（删除重复项）保存到记事本文件中。然后，我需要能够将这些位置带回来并重新创建句子。然而，这必须完成Python。为了更清楚，我将使用我已编写的代码使用示例：

- 输入 -

Would you like to compress or decompress a file? c/d: C
Please type your string using only letters and punctuation: the dog was a dog that jumped over a log
Positions saved to file. Ending code

- 结果 -

1 2 3 4 2 5 6 7 4 8 

the dog was a that jumped over log

我遇到的问题是我无法从这些数字或单词重新创建句子，因为我不明白如何完成这个。到目前为止，我最后一点的代码如下：

    #
    posFile = open ("positions.txt", "r")   #Opens and reads the file with the positions saved
    posFileStr = posFile.read()
    wordFile.close()
    posFile.close()


    #
    word_list = (wordList)                  #Opens and reads the file with the unique words saved
    word_index = (posFileStr)

    recreated = ' '.join([word_list[i-1] for i in word_index])
    positions = [wordList.index(word) for word in sentence]

    print (recreated)
    print (positions)

Answer 1

您的代码不完整，因此无需修复/建议。

这条线对我来说很好看：

recreated = ' '.join([word_list[i-1] for i in word_index])

表示word_index缺少单词。

注意：上面的列表理解不需要括号。如果省略它们，您将获得一个连接迭代的生成器，而无需先分配全新的列表。示例：' '.join(a for a in b)

这是一个解决方案。希望它能帮助您在代码中看到错误。

In [3]: s = 'the dog was a dog that jumped over a log'

In [17]: i = 1
    ...: d = {}
    ...: words = []
    ...: sentence = []
    ...: for w in s.split():
    ...:     if w not in d:
    ...:         d[w] = i
    ...:         i += 1
    ...:         words.append(w)
    ...:     sentence.append(d[w])
    ...:

In [18]: words
Out[18]: ['the', 'dog', 'was', 'a', 'that', 'jumped', 'over', 'log']

In [19]: sentence
Out[19]: [1, 2, 3, 4, 2, 5, 6, 7, 4, 8]

In [20]: ' '.join(words[i - 1] for i in sentence)
Out[20]: 'the dog was a dog that jumped over a log'

In [21]:

从python上的原始位置重新创建一个句子

1 个答案: