Question

我似乎无法弄清楚如何为我的特定问题设置逻辑。我试图计算单词＆＃34; Service＆＃34;的次数。出现但仅在RECORD_CODE为INCIDENT时出现。当RECORD是INCIDENT-UPDATE时，它通常已经在其他地方作为INCIDENT，因此我将它们排除在外以防止重复我的数据。

但是，有少数情况下SUBMIT_METHOD是＆＃34; WEB＆＃34;并且唯一的记录是INCIDENT_UPDATE，我无法弄清楚如何仅查看RECORD =＆＃39; INCIDENT＆＃39;除非特定记录的SUBMIT_METHOD为＆＃34; WEB＆＃34;并且没有该报告的记录＃带有意外记录。这可能是一个简单的问题，我只是在思考它，但我想不出怎么做。任何帮助都会非常感激！

我的查询：

        SELECT column2, count(*) as 'COUNT'
        from Service.Table
        where date between '1/1/17' and '1/31/17'
        and column1 = 'Issue'
        and RECORD = 'INCIDENT'
        group by column2

数据样本：

REPORT #    RECORD    SUBMIT_METHOD   SUBMIT_DATE   COLUMN2
1234       Incident       Web          1/1/2017     Service
1234    Incident-Update   Web          1/1/2017     Service
1235       Incident      Phone        1/15/2017      Other
1235    Incident-Update  Phone        1/15/2017      Other
1236    Incident-Update   Web         1/18/2017     Service

这种情况下的预期输出是：

COLUMN2   COUNT
Service     3

如果我能提供任何其他信息，请告诉我！

Answer 1

您正在寻找group by喜欢的

select column2, count(*)
from tbl1
where SUBMIT_METHOD = 'Web'
group by column2;

Answer 2

您可以使用not exists子查询来确保没有其他行具有相同的Report＃和记录类型INCIDENT：

select  *
from    Service.Table t1
where   date between '1/1/17' and '1/31/17' and
        column1 = 'Issue' and
        (
          record = 'Incident' or
          (
            record = 'Incident-Update' and
            submit_method = 'Web' and
            not exist 
            (
              select  *
              from    Service.Table t2
              where   t2.record = 'INCIDENT' 
                      and t2.[Report #] = t1.[Report #]
            )
          )
        )

Answer 3

 ;With cte(REPORT#,RECORD ,SUBMIT_METHOD,SUBMIT_DATE,COLUMN2)
AS
(
SELECT 1234,'Incident'        ,'Web'  , '1/1/2017' ,'Service'   Union all
SELECT 1234,'Incident-Update' ,'Web'  , '1/1/2017' ,'Service'   Union all
SELECT 1235,'Incident'        ,'Phone', '1/15/2017',  'Other'   Union all
SELECT 1235,'Incident-Update' ,'Phone', '1/15/2017',  'Other'   Union all
SELECT 1236,'Incident-Update' ,'Web'  , '1/18/2017', 'Service'
)
SELECT COLUMN2
    ,CountCOLUMN2
FROM (
    SELECT *
        ,COUNT(COLUMN2) OVER (
            PARTITION BY COLUMN2 ORDER BY COLUMN2
            ) CountCOLUMN2
        ,ROW_NUMBER() OVER (
            PARTITION BY COLUMN2 ORDER BY COLUMN2
            ) Seq
    FROM cte
    ) Dt
WHERE SUBMIT_DATE BETWEEN '1/1/17'
        AND '1/31/17'
    AND RECORD = 'INCIDENT'
ORDER BY 1 DESC

输出

COLUMN2 CountCOLUMN2
--------------------
Service  3
Other    2

如何将条件逻辑应用于Where语句

3 个答案: