RECURSIVE CTE SQL - 查找下一个可用的Parent

Question

我有父子关系SQL表

y

如果我提供输入为LOCATIONDETAIL 6，我应该将RULESETCONFIG值设为30 因为 LOCATIONDETAIL 6，parentid为3，对于LOCATIONDETAIL 3，RULESETCONFIG没有任何价值， LOCATIONDETAIL 3有父1，其值在RULESETCONFIG

中

如果我提供输入为LOCATIONDETAIL 4，我应该得到RULESETCONFIG值15

我有填充树的代码，但不知道如何找到下一个可用的父

LOCATIONDETAIL Table
OID      NAME        PARENTOID
1        HeadSite     0
2        Subsite1     1
3        subsite2     1
4        subsubsite1  2
5        subsubsite2  2
6        subsubsite3  3

RULESETCONFIG
OID     LOCATIONDETAILOID   VALUE
1          1                30
2          4                15

Answer 1

这应该做的工作：

;with LV as (
 select OID ID,PARENTOID PID,NAME NAM, VALUE VAL FROM LOCATIONDETAIL
 left join RULESETCONFIG ON LOCATIONDETAILOID=OID
),    GH as (
 select ID gID,PID gPID,NAM gNAM,VAL gVAL from LV where ID=@OID
union all 
 select ID,PID,NAM,VAL FROM LV INNER JOIN GH ON gVAL is NULL AND gPID=ID
)
select * from GH WHERE gVAL>0

点击此处查看小演示：http://rextester.com/OXD40496

Answer 2

这将返回具有值的下一个父级。如果要查看全部，请从最终选择中删除前1个。

<强> dbFiddle

示例

Declare @Fetch int = 4               

;with cteHB as (
      Select OID
            ,PARENTOID
            ,Lvl=1
            ,NAME 
      From   LOCATIONDETAIL 
      Where  OID=@Fetch
      Union  All
      Select R.OID
            ,R.PARENTOID
            ,P.Lvl+1
            ,R.NAME 
      From   LOCATIONDETAIL R
      Join   cteHB P on P.PARENTOID = R.OID)
Select Top 1
       Lvl = Row_Number() over (Order By A.Lvl Desc )
      ,A.OID
      ,A.PARENTOID
      ,A.NAME
      ,B.Value
From cteHB A
Left Join RULESETCONFIG B on A.OID=B.OID
Where B.VALUE is not null
  and A.OID <> @Fetch
Order By 1 Desc

@ Fetch = 4

时返回

Lvl OID PARENTOID   NAME        Value
2   2   1           Subsite1    15

@ Fetch = 6

时返回

Lvl OID PARENTOID   NAME        Value
1   1   0           HeadSite    30