Question

在我的personDetails.cshmtl文件中，我有以下表格：

<form id="userUpdateForm" method="post">
    <fieldset>
        <legend>User Details</legend>
        <input type="checkbox" name="authorisedCheckbox" value="Authorised" id="authCheck" />Authorised<br />
        <input type="checkbox" name="enabledCheckbox" value="Enabled" id="eCheck" />Enabled<br />
    </fieldset>
    <fieldset>
        <input type="hidden" name="personId" id="idCheck" value='@ViewData["personId"]'>
    </fieldset>
    <input type="submit" value="Save Changes" name="Save Changes">
    <button type="button">Cancel</button>
</form>

然后我在页面的下方继续使用Javascript，如下所示：

$('#userUpdateForm').submit(function (e) {
        var personDetails = {
            Enabled: $('#eCheck').val(),
            Authorised: $('#authCheck').val(),
            Id: $('#idCheck').val()
        };

        $.ajax({
            type: "POST",
            url: '<%= Url.Action("submitForm", "Home") %>',
            data: JSON(personDetails),
            //contentType: "application/json; charset=utf-8",
            dataType: "json",
            success: function (result) {
                '@Url.Action("Index", "Home")';
            },
            error: function (result) {
                alert("A problem occured when submitting the form.");
            }
        });

        return false;
    });

Javascript意味着在点击“提交”按钮时触发。首先，'HomeController'中的方法'submitForm'被触发，然后在'HomeController'中重定向回'Index'，它只输出一个视图。

'submitForm'目前类似于以下内容：

       [HttpPost]
        public ActionResult submitForm(JsonResult jsonForm)
        {
            System.Diagnostics.Debug.WriteLine("made it here");
            System.Diagnostics.Debug.WriteLine(jsonForm);
            return View();
        }

所以我的问题是：我目前的表格中缺少什么才能使AJAX事件发生？我很确定它当前没有被触发，因为控制台没有任何警报和输出，它应该击中它的方法。

我宁愿不要过多地更改表单本身，因为我目前有另外一些Javascript设置复选框以在适当的时候检查onload。

编辑：我用Stephen Muecke的建议修正了这个方法。我在这里要做的是：点击按钮 - ＆gt;将详细信息提交到我的submitForm方法 - ＆gt; submitForm方法需要详细信息并在数据库中执行一些操作 - ＆gt;完成后返回成功 - ＆gt;成功时，从personDetails.cshtml重定向到index.cshtml。

Answer 1

您需要创建一个其他类，该类应包含您要发布到submitForm操作方法的所有属性。

目前您使用的JsonResult类不包含您尝试发布的属性，因此ModelBinder不会绑定数据。参考Model Binder ..好文章......喜欢它....

ld: warning: arm64 function not 4-byte aligned: ltmp0 from /Users/user/unityWorkspace/GoodTest2/NOgpgs/Libraries/libiPhone-lib.a(unwind_test_arm64.o)
ld: warning: arm64 function not 4-byte aligned: _unwind_tester from /Users/user/unityWorkspace/GoodTest2/NOgpgs/Libraries/libiPhone-lib.a(unwind_test_arm64.o)
Undefined symbols for architecture arm64:
  "_kSecValueData", referenced from:
      -[GTMOAuth2Keychain setPassword:forService:accessibility:account:error:] in GoogleSignInDependencies(GTMOAuth2ViewControllerTouch_5e9c07ce1f20710c59c1499209a8b99a.o)
  "_SecTrustEvaluate", referenced from:
      ___70+[GTMSessionFetcher evaluateServerTrust:forRequest:completionHandler:]_block_invoke in GoogleSignInDependencies(GTMSessionFetcher_28beddf8a47a0abe7f4eaa9a5c9cb75b.o)
  "_kSecAttrAccessible", referenced from:
      -[GTMOAuth2Keychain setPassword:forService:accessibility:account:error:] in GoogleSignInDependencies(GTMOAuth2ViewControllerTouch_5e9c07ce1f20710c59c1499209a8b99a.o)
  "_SecItemAdd", referenced from:
      -[GTMOAuth2Keychain setPassword:forService:accessibility:account:error:] in GoogleSignInDependencies(GTMOAuth2ViewControllerTouch_5e9c07ce1f20710c59c1499209a8b99a.o)
  "_SecItemDelete", referenced from:
      -[GTMOAuth2Keychain removePasswordForService:account:error:] in GoogleSignInDependencies(GTMOAuth2ViewControllerTouch_5e9c07ce1f20710c59c1499209a8b99a.o)
  "_kSecReturnData", referenced from:
      -[GTMOAuth2Keychain passwordForService:account:error:] in GoogleSignInDependencies(GTMOAuth2ViewControllerTouch_5e9c07ce1f20710c59c1499209a8b99a.o)
  "_kSecClass", referenced from:
      +[GTMOAuth2Keychain keychainQueryForService:account:] in GoogleSignInDependencies(GTMOAuth2ViewControllerTouch_5e9c07ce1f20710c59c1499209a8b99a.o)
  "_SecItemCopyMatching", referenced from:
      -[GTMOAuth2Keychain passwordForService:account:error:] in GoogleSignInDependencies(GTMOAuth2ViewControllerTouch_5e9c07ce1f20710c59c1499209a8b99a.o)
  "_kSecAttrGeneric", referenced from:
      +[GTMOAuth2Keychain keychainQueryForService:account:] in GoogleSignInDependencies(GTMOAuth2ViewControllerTouch_5e9c07ce1f20710c59c1499209a8b99a.o)
  "_kSecAttrAccessibleAfterFirstUnlockThisDeviceOnly", referenced from:
      +[GTMOAuth2ViewControllerTouch saveParamsToKeychainForName:accessibility:authentication:error:] in GoogleSignInDependencies(GTMOAuth2ViewControllerTouch_5e9c07ce1f20710c59c1499209a8b99a.o)
  "_kSecMatchLimitOne", referenced from:
      -[GTMOAuth2Keychain passwordForService:account:error:] in GoogleSignInDependencies(GTMOAuth2ViewControllerTouch_5e9c07ce1f20710c59c1499209a8b99a.o)
  "_kSecAttrService", referenced from:
      +[GTMOAuth2Keychain keychainQueryForService:account:] in GoogleSignInDependencies(GTMOAuth2ViewControllerTouch_5e9c07ce1f20710c59c1499209a8b99a.o)
  "_kSecClassGenericPassword", referenced from:
      +[GTMOAuth2Keychain keychainQueryForService:account:] in GoogleSignInDependencies(GTMOAuth2ViewControllerTouch_5e9c07ce1f20710c59c1499209a8b99a.o)
  "_kSecRandomDefault", referenced from:
      -[GIDSignIn randomString] in GoogleSignIn(GIDSignIn.o)
  "_kSecAttrAccount", referenced from:
      +[GTMOAuth2Keychain keychainQueryForService:account:] in GoogleSignInDependencies(GTMOAuth2ViewControllerTouch_5e9c07ce1f20710c59c1499209a8b99a.o)
  "_kSecMatchLimit", referenced from:
      -[GTMOAuth2Keychain passwordForService:account:error:] in GoogleSignInDependencies(GTMOAuth2ViewControllerTouch_5e9c07ce1f20710c59c1499209a8b99a.o)
  "_SecRandomCopyBytes", referenced from:
      -[GIDSignIn randomString] in GoogleSignIn(GIDSignIn.o)
ld: symbol(s) not found for architecture arm64
clang: error: linker command failed with exit code 1 (use -v to see invocation)

Answer 2

示例：

型号：

public class MyModel{
        public string Id {get;set;}
        public string Authorised {get;set;}
        public string Enabled {get;set;}
    }

动作：

[HttpPost]
        public ActionResult submitForm(MyModel model)
        {
            System.Diagnostics.Debug.WriteLine("made it here");
            System.Diagnostics.Debug.WriteLine(jsonForm);
            return View();
        }

脚本：

$('#userUpdateForm').submit(function (e) {
        var personDetails = {
            Id: $('#idCheck').val(),
            Authorised: $('#authCheck').val(),
            Enabled: $('#eCheck').val()
        };

        $.ajax({
            type: "POST",
            url: '@Url.Action("submitForm", "Home")',
            contentType: "application/json",
            data: JSON.stringify({ model: personDetails })
            success: function (result) {
                window.location.href = "/home/index/";              
            },
            error: function (result) {
                alert("A problem occured when submitting the form.");
            }
        });

        return false;
    });

ASP.NET MVC - AJAX提交表单不会触发相应的事件

2 个答案: