我有一个结构:
type User struct {
ID int `json:"id"`
Username string `json:"username"`
About string `json:"about"`
IsAdmin bool `json:"is_admin"`
Status int `json:"status"`
......
}
A:= User{1,"admin", "I am a admin",status: 1,....}
B:= User{ID:1, Username: "UserBBBB"}
...enter code here...
B is {1, "UserBBBB", "I am a admin", 1, ...(same value in A)}
对象B有一些属性,包括nil(string),false(bool),0(int),... 我想检查B的字段是否为未分配值,该字段将在A中接收相同字段的值,
示例:
B'关于字段是零;
A'关于字段是"我是管理员" 我想B' s关于字段是"我是管理员"。
我可以写代码:
if len(B.About) == 0 {
B.About = A.About
} 与其他领域类似,我不想逐步检查所有领域。
答案 0 :(得分:1)
package main
import (
"errors"
"fmt"
"log"
"reflect"
"time"
)
type User struct {
ID int `json:"id"`
Username string `json:"username"`
About string `json:"about"`
IsAdmin bool `json:"is_admin"`
Status int `json:"status"`
Date *time.Time
}
func main() {
now := time.Now()
ua := User{
ID: 1,
Username: "admin",
About: "I am an admin",
IsAdmin: true,
Status: 1,
Date: &now,
}
ub := User{
Username: "user",
}
fmt.Printf("ua: %+v\n", ua)
fmt.Printf("ub: %+v\n", ub)
err := Replace(ua, &ub)
if err != nil {
log.Fatal(err)
}
fmt.Printf("\nua: %+v\n", ua)
fmt.Printf("ub: %+v\n", ub)
}
// IsZeroOfUnderlyingType return wether x is the is
// the zero-value of its underlying type.
func IsZeroOfUnderlyingType(x interface{}) bool {
return reflect.DeepEqual(x, reflect.Zero(reflect.TypeOf(x)).Interface())
}
// Replace replaces all fields of struct b that have a
// zero-value with the corresponding field value from a.
// b must be a pointer to a struct.
func Replace(a, b interface{}) error {
// Check a.
va := reflect.ValueOf(a)
if va.Kind() != reflect.Struct {
return errors.New("a is not a struct")
}
// Check b.
vb := reflect.ValueOf(b)
if vb.Kind() != reflect.Ptr {
return errors.New("b is not a pointer")
}
// vb is a pointer, indirect it to get the
// underlying value, and make sure it is a struct.
vb = vb.Elem()
if vb.Kind() != reflect.Struct {
return errors.New("b is not a struct")
}
for i := 0; i < vb.NumField(); i++ {
field := vb.Field(i)
if field.CanInterface() && IsZeroOfUnderlyingType(field.Interface()) {
// This field have a zero-value.
// Search in a for a field with the same name.
name := vb.Type().Field(i).Name
fa := va.FieldByName(name)
if fa.IsValid() {
// Field with name was found in struct a,
// assign its value to the field in b.
if field.CanSet() {
field.Set(fa)
}
}
}
}
return nil
}
<强>输出强>
ua: {ID:1 Username:admin About:I am an admin IsAdmin:true Status:1 Date:2017-05-11 17:47:30.805657327 +0200 CEST}
ub: {ID:0 Username:user About: IsAdmin:false Status:0 Date:<nil>}
ua: {ID:1 Username:admin About:I am an admin IsAdmin:true Status:1 Date:2017-05-11 17:47:30.805657327 +0200 CEST}
ub: {ID:1 Username:user About:I am an admin IsAdmin:true Status:1 Date:2017-05-11 17:47:30.805657327 +0200 CEST}
答案 1 :(得分:-1)
如果我正确理解你要完成的任务,你应该更好地使用指向对象而不是对象的指针。
例如,
A := &User{1,"admin", "I am a admin",status: 1,....}
if A != nil {
fmt.Println(A)
} else {
fmt.Println("nil object")
}
没有理由检查对象的字段是否为默认值。