Question

我正在创建一个存储过程。我有这种格式的数据

InteractiionId（pk）EmployeeId（fk）原因

1                   107           66
2                   107           68
3                   107           66,69
4                   98           71
5                   98           71
6                   98           69,71,68 
7                   90           68 
8                   90           69,68 
9                   90           66,71,68

我需要为每个员工找到这样的原因

EmployeeID ReasonsCount

  107    66(2)
    107     68(1)
    107     69(1) 
    98     71(3)
    98     68(1)
    98     69(1)
    90     68(3)
    90     69(1)
    90     66(1)
    90     71(1)

我想这样做：

select IdEmployee, E.FirstName,E.LastName,  count(reasons), Reasons FROM Interaction I
 LEFT JOIN Employee E
 ON I.IdEmployee = E.Id


-- where
 --    IdEmployee = 95 OR 
--    IdEmployee = 98 OR
  --  IdEmployee = 107
group by  IdEmployee, E.FirstName,E.LastName, Reasons

但它不起作用。请提出解决方案。

感谢。

Answer 1

;with cte
as
(
select * from #temp t
cross apply
SplitStrings_Numbers(c,',') b
)
select b,cast(item as varchar(10))+' ('+ cast(count(item) as varchar(10))+')' as cnt
from
cte
group by b,item

我使用split strings function来分割值

Answer 2

您可以像这样使用内联拆分字符串

DECLARE @SampleData AS TABLE
(
   InteractiionId int,
   EmployeeId int ,
   Reasons varchar(200)
)

INSERT INTO @SampleData
VALUES
  (1, 107, '66'),
  (2, 107, '68'),
  (3, 107, '66,69'),
  (4, 98 , '71'),
  (5, 98 , '71'),
  (6, 98 , '69,71,68'), 
  (7, 90 , '68'), 
  (8, 90 , '69,68'), 
  (9, 90 , '66,71,68')

;WITH temp AS 
(
   SELECT  *,
         CAST('<X>' + replace(sd.Reasons, ',','</X><X>') +'</X>'  AS XML ) AS XmlValue
   FROM @SampleData sd
)
SELECT  t.EmployeeId, CONCAT(c.[Value], '(', count(*), ')') 
FROM temp t
CROSS APPLY
(
   SELECT t.x.value('.', 'varchar(100)') AS Value
   FROM t.XmlValue.nodes('X') AS t(x)
) c
GROUP BY t.EmployeeId, c.[Value]
ORDER BY t.EmployeeId desc

演示链接：http://rextester.com/EHL21890

Answer 3

;With cte(InteractiionId, EmployeeId, Reasons)
 AS
(
SELECT 1, 107,  '66'        UNION ALL
SELECT 2, 107,  '68'        UNION ALL
SELECT 3, 107,  '66,69'     UNION ALL
SELECT 4, 98 , '71'         UNION ALL
SELECT 5, 98 , '71'         UNION ALL
SELECT 6, 98 , '69,71,68'   UNION ALL
SELECT 7, 90 , '68'         UNION ALL
SELECT 8, 90 , '69,68'      UNION ALL
SELECT 9, 90 , '66,71,68' 
)

,CteCount AS (
    SELECT a.InteractiionId
        ,a.EmployeeId
        ,Split.a.value('.', 'VARCHAR(100)') AS Reasons
    FROM (
        SELECT InteractiionId
            ,EmployeeId
            ,CAST('<M>' + REPLACE(Reasons, ',', '</M><M>') + '</M>' AS XML) AS Reasons
        FROM cte
        ) AS A
    CROSS APPLY Reasons.nodes('/M') AS Split(a)
    )

    SELECT EmployeeId
    ,CONCAT(Reasons,'(' ,ReasonCounts,')') AS ReasonsCount
     FROM (
    SELECT EmployeeId,Reasons,ReasonCounts FROM 
       (
        SELECT DISTINCT EmployeeId,Reasons
            ,COUNT(Reasons) OVER (PARTITION BY EmployeeId,Reasons ORDER BY EmployeeId
                ) AS ReasonCounts
        FROM CteCount
        ) Dt
    ) Final
ORDER BY Final.EmployeeId DESC

输出

EmployeeId    ReasonsCount
------------------------
107             66(2)
107             68(1)
107             69(1)
98              68(1)
98              69(1)
98              71(3)
90              66(1)
90              68(3)
90              69(1)
90              71(1)

group by逗号分隔的TSQL中的ID列表无法正常工作

3 个答案: