Question

我的模型看起来像这样：

getMap :: M2 -> Int -> M1 
getMap = (fromJust .) . flip M.lookup

现在，从这个模型中，我得到了所有class AddCoffee(models.Model): user = models.CharField(max_length=50) coffee_name = models.CharField(max_length=50) coffee_price = models.CharField(max_length=10) s：

coffee_name

现在，我想要做的事情（即使有一些与SO密切相关的主题，我也无法找到任何方法）：

生成coffee_names = AddCoffee.objects.values_list('coffee_name', flat=True) len(coffee_names) s，标签为每个咖啡名称，值为0到50之间的列表。如下所示：
```
ChoiceField
```

我怎样才能做到这一点？对于我如何在模型/视图中存储此动态字段后，我的脑子里有些含糊不清。

我试过了：

class RequestCoffeeForm(forms.Form):
    coffee_names = AddCoffee.objects.values_list('coffee_name', flat=True)

    for name in coffee_names:
        forms.ChoiceField(label="{}".format(name),
                          choices=[x for x in range(51)])

    """
    Suppose coffee_names = ["ABC", "DEF"]

    I should have two `ChoiceFields` as follows:

    ABC = forms.ChoiceField(label="ABC", choices=[x for x in range(51)])
    DEF = forms.ChoiceField(label="DEF", choices=[x for x in range(51)])
    """

然后在我的视图中调用：

class RequestCoffeeForm(forms.Form):
    coffee_names = AddCoffee.objects.values_list('coffee_name', flat=True)

    for name in coffee_names:
        name = forms.ChoiceField(label="{}".format(name), choices=((str(x), x) for x in range(51)))

然后在我的模板中：

@login_required(login_url="login/")
def request_coffee_page(request):
    form = RequestCoffeeForm(request.POST or None)

    return render(request, "request_coffee.html", {'form': form})

以上仅打印最后一个coffee_name。我怎样才能打印出来？

Answer 1

class RequestCoffeeForm(forms.Form):
    COFFEE_CHOICES = []
    coffee_names = AddCoffee.objects.values_list('coffee_name', flat=True)

    for name in coffee_names:
        COFFEE_CHOICES.append((str(name).lower(), str(name)))
    forms.ChoiceField(choices=CHOICES_LIST)

choices必须是iterable of 2-tuples。有关示例，请参阅here。

Answer 2

我没有时间尝试，但AFAICT 可能会工作：

var that = this;

data.forEach(function (eachObj) {
  console.log("firms check!");
  console.log(that.firms); // not working
  a = a + eachObj.income; 
  eachObj.name = that.firms[data.firmid - 1].name; // wont work
});

如何在不使用javascript / ajax的情况下在Django中添加N个动态表单字段？

2 个答案: