我有一个实体
title, url, description, text, enabled,...
我只想通过 enabled = true 文章进行搜索。
我怎么能在elastica中做到这一点?
我的配置:
fos_elastica:
clients:
default: { host: localhost, port: 9200 }
indexes:
appletrh:
index_name: 'domain.com'
client: default
types:
products:
properties:
title: { type: string, analyzer: czech }
persistence:
driver: orm
model: Web\MagazineBundle\Entity\Article
elastica_to_model_transformer:
**query_builder_method: search**
provider: ~
listener: ~
finder: ~
EntityRepository 搜索功能
public function search()
{
$qb = $this->createQueryBuilder('p');
$qb->where('p.enabled = true');
return $qb;
}
动作:
public function searchAction(Request $request)
{
$keyword = $request->query->get('keyword');
$finder = $this->get('fos_elastica.finder.domain.articles');
$paginator = $this->get('knp_paginator');
$articles= $finder->createPaginatorAdapter($keyword);
$pagination = $paginator->paginate($articles, $request->query->get('page', 1), 12);
return $this->render('WebMagazineBundle:Search:search.html.twig', ['articles' => $pagination]);
}
我认为这是正确的解决方案,但它仍然会从数据库返回所有数据。
答案 0 :(得分:0)
我觉得你应该在捆绑配置中使用“provider”而不是“elastica_to_model_transformer”选项,例如:
provider:
query_builder_method: search