Question

也许我的谷歌已关闭。

我有一张桌子：sub_transfer_jobs

job_date        mo_id     sub_quantity   shift_id
2017-05-16      24581     12             1
2017-05-16      86122     8              2
etc.

另一张表：mo_numbers

mo_id     customer
24581     cust1
86122     cust2
68515     cust1
etc.

我有另一张桌子：日历。

This just has a date value for every date

我需要得到的是每位客户每天的金额字符串列表

例如

2017-05-15   cust1   50
2017-05-15   cust2   0
2017-05-16   cust1   22
2017-05-16   cust2   10
etc

根据日期范围

，我将根据客户的情况获得一份明确的客户列表

这是我的地方，但在子查询上有问题

SELECT `sub_transfer_jobs`.`sub_quantity`, `sub_transfer_jobs`.`job_date`, `sub_transfer_jobs`.`shift_id`, `mo_numbers`.`customer`
FROM `sub_transfer_jobs`
join mo_numbers on `mo_numbers`.`mo_id` = `sub_transfer_jobs`.`mo_id`
right join calendar on `calendar`.`datefield` = `sub_transfer_jobs`.`job_date`
right join (
    select DISTINCT `mo_numbers`.`customer` from sub_transfer_jobs
    join `mo_numbers` on `mo_numbers`.`mo_id` = `sub_transfer_jobs`.`mo_id`
    where job_date > '2017-04-15'
) as customerList on customerList.customer = mo_numbers.customer
where job_date > '2017-04-15'
group by `mo_numbers`.`customer`, `sub_transfer_jobs`.`job_date`

编辑：更正sql以获得我需要的东西（按逗号分隔分组）

    select basecustomer, GROUP_CONCAT(IFNULL(customerdaytotals.total, 0) ORDER BY datefield ASC) AS total FROM
(select basecustomer, datefield from 
 (select distinct `mo_numbers`.`customer` as basecustomer
  FROM `sub_transfer_jobs`
  JOIN `mo_numbers` on `mo_numbers`.`mo_id` = `sub_transfer_jobs`.`mo_id`
  where `sub_transfer_jobs`.`job_date` > '2017-04-01') as used_customers
 CROSS JOIN (
     SELECT `calendar`.`datefield` from `calendar`
     WHERE `calendar`.`datefield` > '2017-04-01' AND `calendar`.`datefield` < '2017-05-11'
 ) as daterange) as basedata
     LEFT JOIN (
         select `sub_transfer_jobs`.`job_date`, `mo_numbers`.`customer`, sum(`sub_transfer_jobs`.`sub_quantity`) as total
         FROM `sub_transfer_jobs`
         JOIN `mo_numbers` on `mo_numbers`.`mo_id` = `sub_transfer_jobs`.`mo_id`
         GROUP BY `sub_transfer_jobs`.`job_date`, `mo_numbers`.`customer`
     ) as customerdaytotals on customerdaytotals.job_date = basedata.datefield and customerdaytotals.customer = basedata.basecustomer
GROUP BY basecustomer

这给出了

的结果

cust1   0,1857,1262,1166,517,1551,0,0,1469,1670,400,0,0,0,...
cust2   0,123,7,0,7,0,0,0,0,0,0,0,0,0,0,84,70,9,53,3,0,0,4...
cust3   0,0,75,425,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0...
cust4   0,0,41,36,44,26,0,0,0,41,0,0,0,0,0,16,88,12,0,0,0,...
cust5   0,277,552,433,280,491,0,0,124,880,1269,0,0,0,0,495...
cust6   0,255,124,620,184,129,0,0,309,103,88,0,0,0,0,118,2...
cust7   0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,2,0,0,0,0,0,0,0,...
cust8   0,209,123,15,84,296,0,0,296,15,262,0,0,0,0,301,200,...

Answer 1

您需要使用CROSS JOIN来获取客户和日期的所有组合。然后LEFT JOIN使用查询获取每个客户每个日期的总数。

SELECT m.date, c.customer, IFNULL(t.total, 0) AS total
FROM mo_numbers AS m
CROSS JOIN customer AS c
LEFT JOIN (
    SELECT date, mo_id, SUM(quantity) AS total
    FROM mo_numbers
    GROUP BY date, mo_id
) AS t ON m.mo_id = t.mo_id AND c.mo_id = t.mo_id

甚至在mysql查询中缺少值也需要一行

1 个答案: