Question

我有一个SQL问题，我做了一个我无法解决的触发器，我想为我的数据库做一个坏的过滤器。我做了这个触发器工作正常：

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现在我想这样做，以便从现有的表中选择坏词，从我的数据库中选择'Abusivewords'。此触发器已创建，但不会更改任何内容：

USE dbi353348
GO 

Create TRIGGER trChangeAbusiveWordzondertable
ON Post
AFTER INSERT
AS

    DECLARE @Posttekst varchar(300);
    DECLARE @AccountID int;
    DECLARE @PostID int;
    SELECT @Posttekst=i.Post FROM inserted i;
    SELECT @AccountID=i.Account_ID FROM inserted i;
    SELECT @PostID=i.Post_ID FROM inserted i;
BEGIN

DECLARE @AbusiveWords TABLE(ID INT,Word VARCHAR(10))
INSERT INTO @AbusiveWords (ID,Word) values (1,'kanker'),(2,'tyfus'),(3,'tering'),(4,'kut'),(5,'lul'),(6,'eikel'),(7,'klootzak'),(8,'hoer'),(9,'flikker'),(10,'mongool'),(11,'slet'),(12,'bitch');

UPDATE @AbusiveWords
SET @Posttekst=REPLACE(@Posttekst,Word,REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(Word,'A','#'),'E','%'),'I','$'),'O','*'),'U','@')) 

UPDATE Post
SET Post = @Posttekst
WHERE Post_ID = @PostID

END

我在更新声明中的某处确认错误。

Answer 1

更新@Posttekst的问题应该是来自AbusiveWords的字段

UPDATE AbusiveWords
SET WORD=REPLACE(@Posttekst,Word,REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(Word,'A','#'),'E','%'),'I','$'),'O','*'),'U','@'))

SQL触发器与现有表

1 个答案: