Question

我需要运行两个语句来返回我需要的数据。下面的代码将返回除了可以从不同表中检索的count列之外的所有需要的代码。

如何在同一代码中运行这两个语句以检索计数？

以下是我的代码：

 <?php

  $query =  "SELECT * from $CLIENTS_DATABASE order by id DESC";

  if ($result = mysqli_query($conn, $query)) {

    while ($row = mysqli_fetch_assoc($result)) {

    ?>

        <tr>

        <td><?php echo $row["name"]; ?> </td>
        <td><?php echo $row["url"]; ?> </td>
        <td><?php echo $row["secret"]; ?> </td>
        <td><?php echo $row["count"]; ?> </td>

        </tr>

    <?php    
       }
           mysqli_free_result($result);
      }  
    ?>

我需要的计数数据的另一个陈述是：

$query = "SELECT COUNT(*) as count from visits where id_client='$result[id]'"

感谢您的时间和任何帮助。

Answer 1

加入两个查询。

$query = "SELECT order.*, IFNULL(c.count, 0) AS count
          FROM $CLIENTS_DATABASE AS order
          LEFT JOIN (SELECT id_client, COUNT(*) AS count
                FROM visits
                GROUP BY id_client) AS c
          ON c.id_client = order.id
          ORDER BY order.id DESC";

如何在mysqli_query中运行两个语句

1 个答案: