使用多个preg_match获取字符串的最后一部分

Question

Spotify有两种使用url / identifier的方法。我想得到下面字符串的最后一部分（ID）

example url's:
a. https://play.spotify.com/artist/6mdiAmATAx73kdxrNrnlao
b. spotify:artist:6mdiAmATAx73kdxrNrnlao

无法让下面的代码生效，所以我稍后也可以添加更多选项。我首先尝试使用basename，但显然这不适用于'：'。

$str = "https://play.spotify.com/artist/6mdiAmATAx73kdxrNrnlao";
or:
$str = "spotify:artist:6mdiAmATAx73kdxrNrnlao";

if (
    preg_match('artist/([a-zA-Z0-9]{22})/', $str, $re) ||
    preg_match('artist:([a-zA-Z0-9]{22})/', $str, $re)

) {
  $spotifyId = $re[1];
}

感谢任何帮助！

Answer 1

尝试使用斜杠的网址。如果Spotify字符串使用冒号（$("#input").keydown(function (e) { if (e.which == 13) { alert("enter pressed"); return false; } });），只需将:切换为/函数中的:：

explode()

有用功能的粗略示例如下：

// your url
$url = "https://play.spotify.com/artist/6mdiAmATAx73kdxrNrnlao/blah/blah/blah";

// get path only
$path = parse_url($url)['path'];

// seperate by forward slash
$parts = explode('/', $path);

// go through them and find string with 22 characters
$id = '';
foreach ($parts as $key => $value) {
    if (strlen($value) === 22 ) {
        // found it, now store it
        $id = $value;
        break;
    }
}

结果：

function getSpotifyId($spotifyUrl) { // check for valid url if (!filter_var($spotifyUrl, FILTER_VALIDATE_URL)) { // split using colon $parts = explode(':', parse_url($spotifyUrl)['path']); } elseif (filter_var($spotifyUrl, FILTER_VALIDATE_URL)) { // split using forward slash $parts = explode('/', parse_url($spotifyUrl)['path']); } // loop through segments to find id of 22 chars foreach ($parts as $key => $value) { // assuming id will always be 22 characters if (strlen($value) === 22 ) { // found it, now return it return $value; } } return false; } $id1 = getSpotifyId('http://localhost/xampp/web_development/6mdiAmATAx73kdxrNrnlao/stack.php'); $id2 = getSpotifyId('spotify:artist:6mdiAmATAx73kdxrNrnlao'); $id3 = getSpotifyId('My name is tom');

$id1 = '6mdiAmATAx73kdxrNrnlao'

$id2 = '6mdiAmATAx73kdxrNrnlao'