Question

我有一棵这样的树：

repo
|-- dir
|   |-- main_script.sh
|   |-- subdir
|   |   |-- scritp1.sh
|   |   |-- script2.sh

我想在script1.sh中输入script2.sh，在main_script.sh中输入source1.sh，然后从repo调用main_script：

$ pwd
.../repo
$ bash ./dir/main_script.sh

问题在于以下脚本：

main_script.sh：

#!/usr/bin/env bash
source ./subdir/script1.sh

script1.sh：

#!/usr/bin/env bash
source script2.sh

script2.sh：

#!/usr/bin/env bash
echo "Something useful"

我收到错误./dir/main_script.sh: line 2: ./subdir/script1.sh: No such file or directory。似乎bash正在寻找不与main_script.sh相关但与工作目录相关的子目录。我可以使用接受的答案表单this question或this blog post更改第一个脚本以获取脚本的位置，使main_script.sh看起来像这样：

#!/usr/bin/env bash
MYDIR="$( cd "$( dirname "${BASH_SOURCE[0]}" )" && pwd )"
source "${MYDIR}/subdir/script1.sh"

但是我在script1.sh中获取script2.sh时遇到错误：

...repo/dir/subdir/script1.sh: line 2: script2.sh: No such file or directory

因为bash似乎在工作目录中寻找script2.sh。

我不想在每个脚本中嵌入目录结构。那么，问题是如何正确地在bash中导入相关脚本？

Answer 1

PATH受source命令的尊重。因此，您只能在一个地方编辑它，新的PATH将由所有其他人继承：

mydir=${BASH_SOURCE#/*}            # the normalization being done previously was needless
                                   # (and all-caps names are reserved for variables with
                                   # meaning to the shell or operating system).

PATH="$mydir:$mydir/subdir:$PATH"  # no export needed for a variable already in environment

source script1.sh                  # use non-qualified path

如何在应用程序的目录树中使源位置无关？

1 个答案: