Question

我正在处理一个python3和tkinter项目。我想要它，所以当你双击一个列表框项目时，它会运行一个相应的文件。如：

doubleclick Notepad Clone＆gt;运行notepadclone.py，它位于给定的目录中。请帮忙！

#~~PyKit with ListBox View (test)~~#
from tkinter import *
import sys
import os
import webbrowser
import subprocess
from subprocess import run
from subprocess import call


appdir = "./apps"

master = Tk()


scrollbar = Scrollbar(master)
scrollbar.pack(side=RIGHT, fill=Y)

listbox = Listbox(master, yscrollcommand=scrollbar.set)

listbox.insert(END, "Double-Click an item to open it:")

for item in ["one", "two", "three", "four"]:
    listbox.insert(END, item)

listbox.pack(side=LEFT, fill=BOTH)

scrollbar.config(command=listbox.yview)

mainloop()

Answer 1

您可以使用listbox.get('active')获取用户双击的项目，然后使用字典将每个项目与要执行的功能相关联：

import tkinter as tk

def dbclick(event):
    item = listbox.get('active')  #get clicked item
    dbclick_cmds[item]()   # run associated command

appdir = "./apps"

master = tk.Tk()

scrollbar = tk.Scrollbar(master)
scrollbar.pack(side='right', fill='y')

listbox = tk.Listbox(master, yscrollcommand=scrollbar.set)
# dictionary that will contains the function associated to each item
dbclick_cmds = {} 

listbox.insert('end', "Double-Click an item to open it:")
dbclick_cmds["Double-Click an item to open it:"] = lambda: None

for item in ["one", "two", "three", "four"]:
    listbox.insert('end', item)
    dbclick_cmds[item] = lambda i=item: print('run', i)

listbox.pack(side='left', fill='both')

scrollbar.config(command=listbox.yview)

listbox.bind('<Double-1>', dbclick)

master.mainloop()

可点击的列表框项目

1 个答案: