Question

//Add this product into database now

$sql = "INSERT INTO products
                (product_name,price,details,category,
                 subcategory,date_added) 
        VALUES ('$product_name','$price','$details','$category',
                '$subcategory',now())";
        //now() will add todays date in database

if($result = mysqli_query($conn,$sql)){
    $pid = mysqli_insert_id($conn);//Generated an auto-generated id

    //Place image in the folder

    $newname = "$pid.jpg";
    move_uploaded_file($_FILES['fileField']['temp_name'],"../inventory_images/$newname");//$_FILES is a global variable.
    header("location: inventory_list.php");//if you will not include this line then it will add the same product again if you refresh the page.
    exit();
}
else{
    echo"Data didn't inserted in the database";
}

每当我运行代码它运行正常，数据被插入，但当我检查目录中我上传的图像时，该文件夹中没有任何内容。请尽早帮助我。

Answer 1

您的问题是您在move_uploaded_file()函数的<_FILES数组中使用了非现有的出现

move_uploaded_file($_FILES['fileField']['temp_name'],"../inventory_images/$newname");
// - - - - - - - - - - - - -- - - - - - -^^^^^^^^^

应该是

move_uploaded_file($_FILES['fileField']['tmp_name'],"../inventory_images/$newname");

参考文献

http://php.net/manual/en/features.file-upload.post-method.php

这确实应该产生错误。在测试时，如果您在实时服务器上进行测试，则应始终手动打开错误报告。

将ini_set('display_errors', 1); ini_set('log_errors',1); error_reporting(E_ALL); mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);添加到脚本的顶部。这将强制执行任何mysqli_错误生成您可以在浏览器上看到的异常，并且您的浏览器上也会显示其他错误。

我正在尝试使用php

1 个答案: