Question

我正在尝试创建用户之前的活跃时间。每1分钟，时间将在数据库中更新。其中“$ dbtime”是在数据库中更新的时间。这是我尝试的代码，但它只能正确计算30分钟。我想创造一年。保存在数据库中的时间和当前时间格式相同。请帮我解决这个问题。

   $now = new datetime('now');
   $current_time = $now->format('yjgis');

   $my_tim  = $current_time - $dbtime;

switch ($my_tim) {
    case $my_tim < 60 && $my_tim > 0:
       $a_tim = "Online";
       break;
    case $my_tim > 60 && $my_tim < 3600 :
       $a_tim = round($my_tim/60) .' '."Min ago";
       break;
   case $my_tim > 3600 && $my_tim < 86400:
      $a_tim =  round(round($my_tim/60)/60).' '."Hour ago";
      break;
   default:
     $a_tim =  "Offline";
}

Answer 1

您可以使用从CSS Tricks中提取的此功能：

<?php

function ago($time)
{
   $periods = array("second", "minute", "hour", "day", "week", "month", "year", "decade");
   $lengths = array("60","60","24","7","4.35","12","10");

   $now = time();

   $difference     = $now - $time;
   $tense         = "ago";

   for($j = 0; $difference >= $lengths[$j] && $j < count($lengths)-1; $j++) {
       $difference /= $lengths[$j];
   }

   $difference = round($difference);

   if($difference != 1) {
       $periods[$j].= "s";
   }

   return "$difference $periods[$j] 'ago' ";
}

echo ago($dbtime);

?>

在php中计算时间

1 个答案: