Question

朋友们，我几天都在努力解决NoReverseMatch错误，我似乎无法找到代码的错误。我必须说我对Django很新，所以如果你解释一下这个问题的解决方案我会非常感激，所以我可以从中学习：）

错误

NoReverseMatch at /david/Physics/
Reverse for 'subcategory' with keyword arguments '{'subcategory_name': 'a'}' not found. 1 pattern(s) tried: ['david/([a-zA-Z_]+)/(?P<subcategory_name>[a-zA-Z_]+)/$']

category.html：

<h1>The subcategories for {{ category }}</h1>
{% if subcategories %}
    <ul>
    {% for subcategory in subcategories %}
        <li><a href="{% url 'subcategory' subcategory_name=subcategory %}">{{ subcategory }}</a></li>
    {% endfor %}
    </ul>
{% else %}
    <h4>No subcategories for that category</h4>
{% endif %}

urls.py：

from django.conf.urls import url
from . import views

urlpatterns = [
    url(r'^$', views.index, name='index'),
    url(r'^search/$', views.search, name='search'),
    url(r'^browse/$', views.browse, name='browse'),
    url(r'^(?P<category_name>[a-zA-Z_]+)/$', views.view_category, name='category'),
    url(r'^([a-zA-Z_]+)/(?P<subcategory_name>[a-zA-Z_]+)/$',
        views.view_subcategory, name='subcategory'),
    url(r'^([a-zA-Z_]+)/([a-zA-Z_]+)/(?P<information>[a-zA-Z_]+)/$',
        views.view_information, name='information'),
    ]

views.py：

from django.shortcuts import render, get_list_or_404, get_object_or_404
from django.http import HttpResponse 

from .models import Category, Subcategory

# Create your views here.

def index(request):
    return render(request, 'basic_web/index.html')

def search(request):
    return HttpResponse('Here you can search!')

def browse(request):
    categories = Category.objects.all()
    context = {'categories': categories}
    return render(request, 'basic_web/browse.html', context)

def view_category(request, category_name):
    category = get_object_or_404(Category,name__iexact=category_name)
    subcategories = get_list_or_404(Subcategory, parent=category)
    context = {'subcategories': map(lambda x: str(x), subcategories)}
    return render(request, 'basic_web/category.html', context)

def view_subcategory(request, subcategory_name):
    return HttpResponse('You are now browsing subcategory %s' % subcategory_name)

def view_information(request, information):
    return HttpResponse('You are now seeing %s' % information)

如果我需要提供更多信息，请告诉我:) 希望你能帮帮我。

Answer 1

您的子类别网址格式中有两个捕获组（信息中有三个）。这意味着它匹配如下：

/param1/subcategory_name/

您没有为第一个组指定名称，并且您没有在{% url %}标记中传递该名称。你确定要的吗？您应该删除它，以便您的模式变为

r'^(?P<subcategory_name>[a-zA-Z_]+)/$',

如果另一方面你确实需要它，你应该给它一个名字：

 url(r'^(?P<param_name>[a-zA-Z_]+)/(?P<subcategory_name>[a-zA-Z_]+)/$',

并在需要网址时传递：

{% url 'subcategory' param_name=param subcategory_name=subcategory %}

也许第一个参数是类别？

Django NoReverseMatch模板错误

1 个答案: