我想在Sonata管理包中创建一个自定义页面树枝(例如克隆):
我使用本教程:
http://symfony.com/doc/current/bundles/SonataAdminBundle/cookbook/recipe_custom_action.html
这是我的控制器CRUDController.php
:
<?php
// src/AppBundle/Controller/CRUDController.php
namespace AppBundle\Controller;
use Sonata\AdminBundle\Controller\CRUDController as Controller;
class CRUDController extends Controller
{
// ...
/**
* @param $id
*/
public function cloneAction($id)
{
$object = $this->admin->getSubject();
if (!$object) {
throw new NotFoundHttpException(sprintf('unable to find the object with id : %s', $id));
}
// Be careful, you may need to overload the __clone method of your object
// to set its id to null !
$clonedObject = clone $object;
$clonedObject->setName($object->getName().' (Clone)');
$this->admin->create($clonedObject);
$this->addFlash('sonata_flash_success', 'Cloned successfully');
return new RedirectResponse($this->admin->generateUrl('list'));
// if you have a filtered list and want to keep your filters after the redirect
// return new RedirectResponse($this->admin->generateUrl('list', $this->admin->getFilterParameters()));
}
}
但是当我点击克隆时我显示了这个错误:
你能帮助我吗??答案 0 :(得分:2)
我觉得您忘记以正确的方式为此页面配置管理服务,请查看http://symfony.com/doc/current/bundles/SonataAdminBundle/cookbook/recipe_custom_action.html#register-the-admin-as-a-service
因为sonata默认使用SonataAdmin:CRUD控制器,如果你想覆盖控制器,你应该指定一个自定义控制器。
Element Should Be Visible
答案 1 :(得分:1)
您忘记为控制器配置路由。
Sonata Admin必须知道您的新动作才能为其生成路线。为此,您必须在管理类中配置configureRoutes
方法:
class CarAdmin extends AbstractAdmin // For Symfony version > 3.1
{
// ...
/**
* @param RouteCollection $collection
*/
protected function configureRoutes(RouteCollection $collection)
{
$collection->add('clone', $this->getRouterIdParameter().'/clone');
}
}
正如您所看到的,CRUDController中路径的名称与动作的名称相匹配(但没有动作!)。 你有动作的名字:&#39; cloneAction&#39;所以路线的名称是&#34;克隆&#34;。