如何使用spring mvc和hibernate

Question

我想使用spring mvc4和hibernate从jsp插入两个表。

这是我的两个模特班。

1）Employee.java

package com.websystique.springmvc.model;

import java.math.BigDecimal;

import javax.persistence.CascadeType;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.JoinColumn;
import javax.persistence.OneToOne;
import javax.persistence.Table;
import javax.validation.constraints.Digits;
import javax.validation.constraints.NotNull;
import javax.validation.constraints.Size;

import org.hibernate.annotations.Cascade;
import org.hibernate.annotations.Type;
import org.hibernate.validator.constraints.NotEmpty;
import org.joda.time.LocalDate;
import org.springframework.format.annotation.DateTimeFormat;
import com.websystique.springmvc.model.UserLogin;;

@Entity
@Table(name="EMPLOYEE")
public class Employee {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private int id;

    @Size(min=3, max=50)
    @Column(name = "NAME", nullable = false)
    private String name;

    @NotNull
    @DateTimeFormat(pattern="dd/MM/yyyy") 
    @Column(name = "JOINING_DATE", nullable = false)
    @Type(type="org.jadira.usertype.dateandtime.joda.PersistentLocalDate")
    private LocalDate joiningDate;

    @NotNull
    @Column(name = "SALARY", nullable = false)
    private int salary;

    @NotEmpty
    @Column(name = "SSN", unique=true, nullable = false)
    private String ssn;


    @Column(name="emp_id",nullable=true)
    private String emp_id;



    public UserLogin getUserlogin() {
        return userlogin;
    }

    public void setUserlogin(UserLogin userlogin) {
        this.userlogin = userlogin;
    }

    public String getEmp_id() {
        return emp_id;
    }

    public void setEmp_id(String emp_id) {
        this.emp_id = emp_id;
    }

    @OneToOne(targetEntity=UserLogin.class,cascade=CascadeType.ALL)
    @JoinColumn(name="emp_id",referencedColumnName="emp_id",insertable=false, updatable=false)
    private UserLogin userlogin;


    public int getId() {
        return id;
    }

    public void setId(int id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public LocalDate getJoiningDate() {
        return joiningDate;
    }

    public void setJoiningDate(LocalDate joiningDate) {
        this.joiningDate = joiningDate;
    }

    public int getSalary() {
        return salary;
    }

    public void setSalary(int salary) {
        this.salary = salary;
    }

    public String getSsn() {
        return ssn;
    }

    public void setSsn(String ssn) {
        this.ssn = ssn;
    }

    @Override
    public int hashCode() {
        final int prime = 31;
        int result = 1;
        result = prime * result + id;
        result = prime * result + ((ssn == null) ? 0 : ssn.hashCode());
        return result;
    }

    @Override
    public boolean equals(Object obj) {
        if (this == obj)
            return true;
        if (obj == null)
            return false;
        if (!(obj instanceof Employee))
            return false;
        Employee other = (Employee) obj;
        if (id != other.id)
            return false;
        if (ssn == null) {
            if (other.ssn != null)
                return false;
        } else if (!ssn.equals(other.ssn))
            return false;
        return true;
    }

    @Override
    public String toString() {
        return "Employee [id=" + id + ", name=" + name + ", joiningDate="
                + joiningDate + ", salary=" + salary + ", ssn=" + ssn + "]";
    }




}

2）UserLogin.java

package com.websystique.springmvc.model;

import java.io.Serializable;

import javax.persistence.CascadeType;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.JoinColumn;
import javax.persistence.OneToOne;
import javax.persistence.PrimaryKeyJoinColumn;
import javax.persistence.Table;

import org.hibernate.annotations.GenericGenerator;

@Entity
@Table(name="users")
public class UserLogin implements Serializable{

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private int id;

    @Column(name="emp_id", unique=true, nullable=true)
    private String emp_id;



    @Column(name="user_name",nullable=false)
    private String user_name;

    @Column(name="password",nullable=false)
    private String password;



    public int getId() {
        return id;
    }

    public void setId(int id) {
        this.id = id;
    }

    public String getUser_name() {
        return user_name;
    }

    public void setUser_name(String user_name) {
        this.user_name = user_name;
    }

    public String getPassword() {
        return password;
    }

    public void setPassword(String password) {
        this.password = password;
    }


}

这是我的jsp页面（registration.jsp）

<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
    pageEncoding="ISO-8859-1"%>
<%@ taglib prefix="form" uri="http://www.springframework.org/tags/form"%>
<%@ taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core" %>

<html>

<head>
    <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
    <title>Employee Registration Form</title>

<style>

    .error {
        color: #ff0000;
    }
</style>

</head>

<body>

    <h2>Registration Form</h2>

    <form:form method="POST" modelAttribute="employee">
        <form:input type="hidden" path="id" id="id"/>
        <table>
            <tr>
                <td><label for="name">Name: </label> </td>
                <td><form:input path="name" id="name"/></td>
                <td><form:errors path="name" cssClass="error"/></td>
            </tr>
            <tr>
                <td><label for="user_name">User Name: </label> </td>
                <td><form:input path="user_name" id="user_name"/></td>
                <td><form:errors path="user_name" cssClass="error"/></td>
            </tr>
            <tr>
                <td><label for="pwd">Password: </label> </td>
                <td><form:input type="password" path="password" id="password"/></td>
                <td><form:errors path="password" cssClass="error"/></td>
            </tr>
            <tr>
                <td><label for="joiningDate">Joining Date: </label> </td>
                <td><form:input path="joiningDate" id="joiningDate"/></td>
                <td><form:errors path="joiningDate" cssClass="error"/></td>
            </tr>

            <tr>
                <td><label for="salary">Salary: </label> </td>
                <td><form:input path="salary" id="salary"/></td>
                <td><form:errors path="salary" cssClass="error"/></td>
            </tr>

            <tr>
                <td><label for="ssn">SSN: </label> </td>
                <td><form:input path="ssn" id="ssn"/></td>
                <td><form:errors path="ssn" cssClass="error"/></td>
            </tr>

            <tr>
                <td colspan="3">
                    <c:choose>
                        <c:when test="${edit}">
                            <input type="submit" value="Update"/>
                        </c:when>
                        <c:otherwise>
                            <input type="submit" value="Register"/>
                        </c:otherwise>
                    </c:choose>
                </td>
            </tr>
        </table>
    </form:form>
    <br/>
    <br/>
    Go back to <a href="<c:url value='/list' />">List of All Employees</a>
</body>
</html>

这是我的控制器

@RequestMapping(value = {  "/new" }, method = RequestMethod.POST)
public String saveEmployee(@Valid Employee employee,@Valid UserLogin userLogin, BindingResult result,
        ModelMap model) {
    System.out.println("inside controller");
    System.out.println("result>>>> "+result);

    if (result.hasErrors()) {
        System.out.println("inside controller1111111111");
        return "registration";
    }

    if(!service.isEmployeeSsnUnique(employee.getId(), employee.getSsn())){
        System.out.println("inside controller1111111111222222222222222222222");
        FieldError ssnError =new FieldError("employee","ssn",messageSource.getMessage("non.unique.ssn", new String[]{employee.getSsn()}, Locale.getDefault()));
        result.addError(ssnError);
        return "registration";
    }
    String emp="Emp-"+employee.getId()+"-"+employee.getName();
    System.out.println("emp>>> "+emp);
    employee.setEmp_id(emp);

    service.saveEmployee(employee);

    userservice.saveUser(userLogin);

    model.addAttribute("success", "Employee " + employee.getName() + " registered successfully");
    return "success";
}

所以我想将user_name和密码保存到登录表中，其余的数据要保存到另一个表中。是否有人可以帮助我如何将数据插入两个表。我搜索了很多但没有取得丰硕成果。此问题的任何链接也不胜感激。提前致谢

Answer 1

您可以使用实体继承。检查一下http://www.thoughts-on-java.org/complete-guide-inheritance-strategies-jpa-hibernate/ 。选择符合您要求的策略。