Question

我有一个类。我的代码编译正确，但是当我试图从键盘输入这个数组时我的程序停止工作。我认为问题出在内存分配上。如何正确分配内存来解决这个问题？

class group
{
    protected:
        diplomStudent *arr;
        int size;
    public:
        group(int studs)
        {
            arr=new diplomStudent[studs];
            size=studs;
        }
        void setgroup()
        {
            for(int i=0;i<size;i++)
                cin>>arr[i];//'>>' is overloaded for diplomstudent 
        }
     }

重载操作;

friend istream& operator>>(istream& is, diplomStudent& obj)
    {

         is >> obj.surname;
         is >> obj.name;
         is >> obj.patr;
         is >> obj.course;
         is >> obj.rate;
         is >> obj.diplom;
         is >> obj.perscent;
         return is;
    }

主要功能：

int main()
{
group g1(2);
    g1.setgroup();
    return 0;
}

Answer 1

问题必须在类diplomStudent的定义中，但由于您不提供该信息，我们无法确定。我正在为班级的所有成员使用一个字符串，对我来说工作得很好，这里有示例代码：

#include <iostream>
#include <string>

using namespace std;

class diplomStudent
{
public:
    string surname, name, patr, course, rate, diplom, perscent;
    friend istream& operator>>(istream& is, diplomStudent& obj)
    {
        is >> obj.surname; is >> obj.name; is >> obj.patr; is >> obj.course;
        is >> obj.rate; is >> obj.diplom; is >> obj.perscent;
        return is;
    }
};

class group
{
protected:
    diplomStudent *arr;
    int size;
public:
    group(int studs) : arr(new diplomStudent[studs]), size(studs) {}
    ~group() { delete[] arr; }

    void setGroup()
    {
        for (int i = 0; i < size; ++i)
            cin >> arr[i];          //'>>' is overloaded for diplomStudent 
    }

    void printGroup()
    {
        for (int i = 0; i < size; ++i)
            cout << arr[i].surname << " " << arr[i].name << " " << arr[i].patr << " " << arr[i].course
            << " " << arr[i].rate << " " << arr[i].diplom << " " << arr[i].perscent << endl;
    }
};

int main()
{
    group g1(2);
    g1.setGroup();
    g1.printGroup();
    return 0;
}

对象数组的内存分配

1 个答案: