Question

我是OneSignal通知的新手我必须通过我的phonegap应用程序发送通知消息。我知道如何发送新消息流程以通过信号仪表板发送通知的过程。

任何人都可以帮助我使用ajax调用从应用程序中执行此操作三江源。

Answer 1

您可以使用对 https://onesignal.com/api/v1/notifications 的ajax调用来触发来自应用的通知。

var request = $.ajax({
  url: "https://onesignal.com/api/v1/notifications",
   headers: {
        'Authorization':'Basic ONESIGNAL_REST_API_KEY',
        'Content-Type':'application/json'
    },
  type: "POST",
  data: {"app_id" : "Your APP ID","contents":{"en":"message"},"included_segments":["All"],"data":{"abc": "123", "foo": "bar"}},
  dataType: "application/json"
});

request.done(function(msg) {
  console.log("success");
});

request.fail(function(jqXHR, textStatus) {
  console.log( "Request failed: " + textStatus );
});

希望它会对你有所帮助。

Answer 2

var jsonBody = {
                  "app_id": "Onesignal App Id",
                  "include_player_ids": ["App Playerid"],
                  "headings": {
                                "en": "Sump"
                              },
                  "contents": {
                                "en": " Sump Level is 'Sumpper' "
                              }
              };
                var request = $.ajax({
                      url: "https://onesignal.com/api/v1/notifications",
                      headers: {
                            'Authorization':'Basic REST API Key',
                            'Content-Type':'application/json',
                            'Access-Control-Allow-Headers': 'SDK-Version',
                            'Access-Control-Allow-Origin': '*'
                        },
                      type: "POST",
                      data: JSON.stringify(jsonBody),
                      dataType: "json"
                });
                console.log(request);

                    request.success(function(msg) {
                      console.log("success");
                    });

                    request.error(function(jqXHR, textStatus ) {
                      console.log( "Request failed: " + textStatus );

                    });

如何使用ajax在phonegap应用程序中生成信号通知消息

2 个答案: