Question

我有一个包含7个功能的表格。最后一个是时间戳。我只想将时间序列数据划分为每个10分钟的相等时隙。所以我可以检查哪个实例属于哪个插槽。

Answer 1

import pandas as pd
import datetime as dt

# Create reproduceable example data 
# (in the future, it's better if you do this in your question)
first_timestamp = pd.to_datetime('1/1/2011 00:00')

timestamps = pd.date_range(first_timestamp, periods=100, freq='1Min')
other_data = np.random.randint(0,10,size=(100,))

df = pd.DataFrame({'timestamp': timestamps,
                   'other_data': other_data})

# Create a timedelta of minutes since first timestamp
# timedeltas have attributes for days and seconds, but not minutes.
df['minutes_since_start'] = (df['timestamp'] - first_timestamp).dt.seconds / 60

# Create groups
df['timestamp group'] = pd.cut(df['minutes_since_start'], bins=range(0,101, 10),include_lowest=True)

# first 3 entries
df.head(5)

输出：

   other_data           timestamp  minutes_since_start timestamp group
0           8 2011-01-01 00:00:00                  0.0         [0, 10]
1           5 2011-01-01 00:01:00                  1.0         [0, 10]
2           7 2011-01-01 00:02:00                  2.0         [0, 10]

从任意时间戳组获取数据，例如开始后70-80分钟

df[df['timestamp group'] == '(70, 80]']

输出：

    other_data           timestamp  minutes_since_start timestamp group
71           1 2011-01-01 01:11:00                 71.0        (70, 80]
72           8 2011-01-01 01:12:00                 72.0        (70, 80]
73           3 2011-01-01 01:13:00                 73.0        (70, 80]
74           0 2011-01-01 01:14:00                 74.0        (70, 80]
75           8 2011-01-01 01:15:00                 75.0        (70, 80]
76           8 2011-01-01 01:16:00                 76.0        (70, 80]
77           0 2011-01-01 01:17:00                 77.0        (70, 80]
78           6 2011-01-01 01:18:00                 78.0        (70, 80]
79           0 2011-01-01 01:19:00                 79.0        (70, 80]
80           5 2011-01-01 01:20:00                 80.0        (70, 80]

熊猫时间系列师

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