Question

我创建了2个函数，每个函数都会掷骰子，然后我在main函数中输出每个骰子的结果。如何将每个骰子的结果一起添加？（我对主要功能中的一行做了评论）

#include<iostream>
#include<cstdlib>
#include<ctime>
using namespace std;

int diceroll1();
int diceroll2();

int main() {


    cout << "you rolled a.\n";
    cout << diceroll1(); cout << endl;
    cout << "and a\n";
    cout << diceroll2(); cout << endl;
    cout << "for a total of:\n";
    cout << diceroll1 + diceroll2 // idk how to sum these two values, and output them, as they are going to be different values each time. 

    system("PAUSE");
    return 0;
}

int diceroll1() {

    int roll1;
    srand(time(0));
    const int numberOfRolls = 1;

    for (int i = 0; i < numberOfRolls; i++) {

        roll1 = 1 + (rand() % 6);
        return roll1;


    }

}
int diceroll2() {

    int roll2;
    srand(1+time(0));
    const int numberOfRolls = 1;

    for (int i = 0; i < numberOfRolls; i++) {

        roll2 = 1 + (rand() % 6);
        return roll2;

    }
}

Answer 1

你可以这样做：

diceroll1() + diceroll2()

因为编译器将其视为值diceroll1（）返回+ diceroll2（）的值;

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1 个答案: