Question

目前我有这个：

class MySerializer(serializers.ModelSerializer):

    class Meta:
        model = MyModel
        fields = (
            'id', 'f0', 'f1', 'f2')

它返回的内容如下：

{
    "count": 6242,
    "previous": null,
    "total_pages": 209,
    "results": [
        {
            "id": 63915,
            "f0": "Some stuff"
            .....
         },
        {
            "id": 63916,
            "f0": "Some other stuff"
            .....
         }....            

     ]
}

这很好，但我注意到序列化数据实际上是非常昂贵的，所以我想预先计算它。到目前为止，我已经设法预先计算并将其存储在我的模型的jsonfield中，问题是我的API现在正在返回{＆＃39; json_repersentation＆＃39;：{myold_response}}

class MySerializer(serializers.ModelSerializer):

    class Meta:
        model = MyModel
        fields = ('json_representation',)

我的问题是，是否可以更改它，以便它只返回json_representation字段中包含的json而没有＆＃34;开销＆＃34; {＆＃39; json_representation＆＃39;：{id：0，f0：label ...}}而只是{id：0，f0：label ...}

Answer 1

您可以覆盖序列化程序grails.plugin.springsecurity.filterChain.chainMap = [ [pattern: '/assets/**', filters: 'none'], [pattern: '/**/js/**', filters: 'none'], [pattern: '/**/css/**', filters: 'none'], [pattern: '/**/images/**', filters: 'none'], [pattern: '/**/favicon.ico', filters: 'none'], [pattern: '/api/**', filters: 'JOINED_FILTERS,-exceptionTranslationFilter,-authenticationProcessingFilter,-securityContextPersistenceFilter'], // Stateless chain [pattern: '/data/**', filters: 'JOINED_FILTERS,-exceptionTranslationFilter,-authenticationProcessingFilter,-securityContextPersistenceFilter'], // Stateless chain [pattern: '/**', filters: 'JOINED_FILTERS,-restTokenValidationFilter,-restExceptionTranslationFilter'] // Traditional chain ]方法：

to_representation

Django RestFramework返回一个预先计算好的json

1 个答案: