我有一个WebAPI 2项目,其中包含几个以Json格式返回数据的API。然后将这些Json文件加载到单独的前端开发机构创建的图形中。这些图形接受以下格式的Json文件:
"colors": {
"Europe": "red",
"North-America": "blue",
"South-America": "green",
"Asia": "purple",
"Other": "grey"
}
我的WebAPI项目将数据输出为Json,但它包含如下属性名称:
"colors": [
{
"Title": "Europe",
"ColorName": "red"
},
{
"Title": "North-America",
"ColorName": "blue"
},
{
"Title": "South-America",
"ColorName": "green"
},
{
"Title": "Asia",
"ColorName": "purple"
},
{
"Title": "Other",
"ColorName": "grey"
}
是否有标准的方法来输出没有属性名称的数据?
我正在使用WebAPI 2的标准安装及其所有默认值,其中包括对Newtonsoft.Json的引用。
答案 0 :(得分:2)
如果您使用的是json.net,一种方法是定义自定义JsonConverter
:
public class Color
{
public string Title { get; set; }
public string ColorName { get; set; }
}
public class ColorsConverter : JsonConverter
{
public override bool CanConvert(Type objectType)
{
return objectType == typeof(Color[]);
}
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
var colors = (Color[]) value;
var temp = colors.ToDictionary(x => x.Title, x => x.ColorName);
serializer.Serialize(writer, temp);
}
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
throw new NotImplementedException();
}
}
然后使用它:
var colors = new[]
{
new Color {Title = "Europe", ColorName = "red"},
new Color {Title = "North-America", ColorName = "blue"},
new Color {Title = "South-America", ColorName = "green"},
new Color {Title = "Asia", ColorName = "purple"},
new Color {Title = "Other", ColorName = "grey"}
};
var json = JsonConvert.SerializeObject(new {colors}, new ColorsConverter());
这将产生这样的json:
{
"colors": {
"Europe": "red",
"North-America": "blue",
"South-America": "green",
"Asia": "purple",
"Other": "grey"
}
}
答案 1 :(得分:0)
如果你解码它 它将是相同的 它们都可以解码为json对象 它是一个有意义的和有希望的帮助
答案 2 :(得分:0)
当你得到api数据时,改变这样......
$(document).ready(function () {
//your api json data
var rootObject = {
"colors": [
{
"Title": "Europe",
"ColorName": "red"
},
{
"Title": "North-America",
"ColorName": "blue"
},
{
"Title": "South-America",
"ColorName": "green"
},
{
"Title": "Asia",
"ColorName": "purple"
},
{
"Title": "Other",
"ColorName": "grey"
}]
}
var jsonArr = [];
for (var i = 0; i < rootObject.colors.length; i++) {
var temp={};
temp[rootObject.colors[i].Title] = rootObject.colors[i].ColorName;
jsonArr.push(temp);
}
var stringJson = JSON.stringify(jsonArr);
alert(stringJson );
});