注意!!

Question

所需的结果是函数或查找字符串列表中句子的位置的方法。

sentence = 'The cat went to the pool yesterday'

structure = ['The cat went,', 'to the pool yesterday.','I wonder if you realize the effect you are having on me. It hurts. A lot.']

例如

def findsentence(sentence, list of strings):
      # do something to get the output, vec of positions to find the sentence in hte string list
return output

findsentence(sentence, structure)
> (0,1) # beacuse the phrase is splitted in the list...

注意!!

挑战不是找到确切的句子。看一下这个例子，这句话是句子位置0的一部分，也是结构张贴1的一部分。

所以这不是一个简单的字符串操作问题。

Answer 1

使用以下内容：

sentence = "foo sam bar go"
structure = ["rq", "foo sam", "bar go", "ca", "da"]

def findsentencelist(sentence, list_of_strings):
    l = []
    for item in list_of_strings:
        if item in sentence:
            l.append(list_of_strings.index(item))
    return l

print str(findsentencelist(sentence, structure))

希望这对你有帮助，Yahli。

编辑：

您的变量存在问题。你的句子必须是一个字符串 - 而不是一个列表。编辑变量并再次尝试此功能：）

第二次编辑：我想我终于明白了你要做的事情。如果这个效果更好，请告诉我。

第三次编辑：耶稣，希望这个可以解决你的问题。让我知道它是否有诀窍:)）

Answer 2

我只是删除structure上的标点符号以使其正常工作：

sentence = 'The cat went to the pool yesterday'

structure = ['The cat went,', 'to the pool yesterday.','I wonder if you realize the effect you are having on me. It hurts. A lot.','Life is too short as it is. In short, she had a cushion job.']

import string

def findsentence(sentence, list_of_strings):
    return tuple(i for i, s in enumerate(list_of_strings) if s.translate(None, string.punctuation) in sentence)


print findsentence(sentence, structure)
# (0, 1)

Answer 3

删除标点符号后。您可以使用此代码获取索引

for i,j in enumerate(structure):
     if j in sentence:
          print(i)

希望这可以解决您的问题。还有其他解决方案，因为python很灵活。

从字符串列表中获取分裂句子的索引

注意!!

3 个答案: