Question

我有两个html模板，它们执行相同的功能，但由两个不同的控制器处理：

主持人控制器处理的第一个html

th:action="@{/someurl}"

管理员控制器处理的第二个HTML

y1=y1+45;// extra line u need to add




CGFloat y1 = 40;
CGFloat x1 = 30.0;
CGRect rect1 = CGRectMake(x1, y1, 100, 30);

for (int i = 0; i < 4; i++)
{

    label = [[UILabel alloc] initWithFrame:rect1];
    label.tag = i+1;
    label.textAlignment = NSTextAlignmentCenter;
    label.backgroundColor = [UIColor blueColor];
    label.textColor = [UIColor whiteColor];
    label.font = [UIFont fontWithName:@"Verdana-Bold" size:17.0];
    label.text = @"Hello";
    label.userInteractionEnabled = YES;

    UITapGestureRecognizer *tap = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(gotTapped:)];
    [label addGestureRecognizer:tap];
    [self.view addSubview:label];

    label2 = [[UILabel alloc] initWithFrame:CGRectMake(150, y1,  50, 30)];

    label2.tag = i+100;
    label2.textAlignment = NSTextAlignmentCenter;
    label2.backgroundColor = [UIColor redColor];
    label2.textColor = [UIColor whiteColor];
    label2.font = [UIFont fontWithName:@"Verdana-Bold" size:8];
    label2.text = [NSString stringWithFormat:@"%@%ld",@"world",(long)label2.tag];
    label2.hidden = YES;
    [self.view addSubview:label2];
    rect1.origin.y += 45;
    y1=y1+45;

    NSLog(@"tag values of label2 are %ld",label2.tag);

}

正如您所看到的，这些模板的区别仅在于-(void)gotTapped:(UITapGestureRecognizer*)sender { NSLog(@"%ld",(((UITapGestureRecognizer *)sender).view.tag)); int num= 99 +(int)(((UITapGestureRecognizer *)sender).view.tag); NSLog(@"%d",num); UILabel *label3 = [self.view viewWithTag:num]; label3.hidden = NO; switch(((UITapGestureRecognizer *)sender).view.tag) { case 1: NSLog(@"Clicked on label 1"); break; case 2: NSLog(@"Clicked on label 2"); NSLog(@"%ld",100 +((UITapGestureRecognizer *)sender).view.tag) ; break; case 3: NSLog(@"Clicked on label 3"); NSLog(@"%ld",100 +((UITapGestureRecognizer *)sender).view.tag) ; break; case 4: NSLog(@"Clicked on label 4"); NSLog(@"%ld",100 +((UITapGestureRecognizer *)sender).view.tag) ; break; } } url：

PostgreSQLDialect

是否可以将来自不同控制器的动态网址使用相同的模板？

Answer 1

有很多不同的方法可以做到这一点......最简单的方法是在控制器中使用相同的模板，并在每个控制器中传递一个包含正确动作的变量。

例如：

// Moderator controller
@RequestMapping(value = "/moderator")
public String moderator(Map<String, Object> model) {
  model.put("action", "/moderator/new-user-form");
  return "new-user-form";
}

// Admin controller
@RequestMapping(value = "/moderator")
public String moderator(Map<String, Object> model) {
  model.put("action", "/admin/new-user-form");
  return "new-user-form";
}

并在html中

<form th:action="@{${action}}">

如果这不合适，您可以将表单本身转换为片段，然后将该操作作为参数传递。像这样：

<!-- Fragment -->
<form th:fragment="userform (action)" th:action="@{${action}}">
  .
  .
  .
</form>

<!-- Including the fragment -->
<div th:replace="fragments/userform :: userform(action='/admin/new-user-form')" />
<!-- or -->
<div th:replace="fragments/userform :: userform(action='/moderator/new-user-form')" />

Thymeleaf：使用与来自不同控制器的动态URL相同的模板

1 个答案: