Question

我制作了一个脚本，为shopify网站构建了一个结帐URL。这是通过附加每个独特的产品变体来实现的。结帐URL中的ID，然后在webbrowser中打开所述URL。要查找变体ID，我需要解析网站的站点地图以获取ID，我目前正在为我正在解析的每个产品的单独线程中执行此操作，但是每增加一个线程所需的时间增加相当于很多（差不多一秒钟）。

为什么会这样？不应该花费大约相同的时间，因为每个线程基本上都做同样的事情吗？

作为参考，一个线程需要大约2.0秒，两个线程2.8s和三个线程大约3.8s

这是我的代码：

import time
import requests
from bs4 import BeautifulSoup
import webbrowser
import threading

sitemap2 = 'https://deadstock.ca/sitemap_products_1.xml'
atc_url = 'https://deadstock.ca/cart/'

# CHANGE SITEMAP TO THE CORRECT ONE (THE SITE YOU ARE SCRAPING)

variant_list = []


def add_to_cart(keywords, size):
    init = time.time()
    # Initialize session
    product_url = ''
    parse_session = requests.Session()
    response = parse_session.get(sitemap2)
    soup = BeautifulSoup(response.content, 'lxml')
    variant_id = 0

    # Find Item
    for urls in soup.find_all('url'):
        for images in urls.find_all('image:image'):
            if all(i in images.find('image:title').text.lower() for i in keywords):
                now = time.time()
                product_name = images.find('image:title').text
                print('FOUND: ' + product_name + ' - ' + str(format(now-init, '.3g')) + 's')
                product_url = urls.find("loc").text

    if product_url != '':
        response1 = parse_session.get(product_url+".xml")
        soup = BeautifulSoup(response1.content,'lxml')
        for variants in soup.find_all('variant'):
            if size in variants.find('title').text.lower():
                variant_id = variants.find('id', type='integer').text
                atc_link = str(variant_id)+':1'
                print(atc_link)
                variant_list.append(atc_link)


    try:
        print("PARSED PRODUCT: " + product_name)

    except UnboundLocalError:
        print("Retrying")
        add_to_cart(keywords, size)


def open_checkout():
    url = 'https://deadstock.ca/cart/'
    for var in variant_list:
        url = url + var + ','
    webbrowser.open_new_tab(url)




# When initializing a new thread, only change the keywords in the args, and make sure you start and join the thread.
# Change sitemap in scraper.py to your websites' sitemap

# If the script finds multiple items, the first item will be opened so please try to be very specific yet accurate.

def main():
    print("Starting Script")
    init = time.time()

    try:
        t1 = threading.Thread(target=add_to_cart, args=(['alltimers','relations','t-shirt','white'],'s',))
        t2 = threading.Thread(target=add_to_cart, args=(['alltimers', 'relations', 'maroon'],'s',))
        t3 = threading.Thread(target=add_to_cart, args=(['brain', 'dead','melter'], 's',))
        t1.start()
        t2.start()
        t3.start()
        t1.join()
        t2.join()
        t3.join()
        print(variant_list)
        open_checkout()
    except:
        print("Product not found / not yet live. Retrying..")
        main()

    print("Time taken: " + str(time.time()-init))

if __name__ == '__main__':
    main()

Answer 1

问题：...一个线程需要大约2.0秒，两个线程2.8s和三个线程大约3.8s

关于您的示例代码，您计算所有threads的总和正如#asettouf指出的那样，有一个开销，这意味着你必须付钱。
但我认为，做这3个任务threaded会更快，因为它一个接一个地做。

线程仍然需要很长时间

1 个答案: