Question

我要求获取子节点的父节点。我需要解析的HTML是biology

例如关于上面的HTML，我需要输出到诸如

之类的文本

N1a parentNode：N1~
N1a1 parentNode：N1a
N1a1a1a1a1a parentNode：N1a1a1a1a1

因为我使用JAVA作为开发语言，所以我指的是使用jsoup，现在我通过这些节点之前的点来解决这个问题，但不幸的是，有些观点并不依赖于规则。所以有人可以解析这个HTMl，谢谢！

直到现在我有代码部分，但代码不好：

try {
        String url = Constants.URL;
        System.out.println(url);
        Connection connection = (Connection) Jsoup.connect(url).userAgent("Mozilla/5.0 (Macintosh; Intel Mac OS X 10_9_2) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/33.0.1750.152 Safari/537.36");
        Document document = connection.get();
        Elements lis = document.select("span.hap");
        Iterator<Element> liIterator =  lis.iterator();

        HashMap<Integer, String> map = new HashMap<>(); //存放点数/当前节点

        //begin
        map.put(0, "N");

        while(liIterator.hasNext()){
            Element element = liIterator.next();
            Element previous;
            if((element.text().contains("N1") || element.text().contains("N2"))) {
                previous = element.previousElementSibling();
                Element parent = element.parent();
                int count=0;
                boolean flag= true;
                if(previous == null) {
                    previous = element.parent().previousElementSibling().children().last();
                }
                while( !previous.tagName().equals("br") && flag) {

                    char[] array = previous.text().toCharArray();
                    for(char point : array) {
                        if(point== '•')
                            count++;
                    }
                    previous = previous.previousElementSibling();
                    if(previous == null) {
                        if(parent.previousElementSibling().children() != null)
                            previous = parent.previousElementSibling().children().last();
                        parent =parent.previousElementSibling();

                    }
                    if( !parent.tagName().equals("br") && previous != null) {
                        if(previous.children() != null) {
                            for( Element element2 :previous.children()) {
                                if(element2.tagName().equals("br"))
                                    flag = false;
                            }
                        }
                    } else {
                        flag = false;
                        previous = parent.previousElementSibling();
                    }




                }

                map.put(count, element.text());
                JsoupUtil.getInstance().writeFile(element.text() + "  Parent Node: " + map.get(count-1));
            }
    } 
}catch (Exception e) {
    e.printStackTrace();
}
}

使用Jsoup来解析不规则的HTML

0 个答案: