来自xlsx文件的DataStructure

时间:2017-05-09 07:49:32

标签: java excel multidimensional-array data-structures apache-poi

我正在开发一个项目,我必须从excel文件中获取文件夹和子文件夹名称,保留层次结构并将它们存储在一个数组中,以使用该数组创建目录结构。

我使用Apache POI读取excel文件。

考虑到我有8个树级,我怎样才能将它们存储到数组中?

例如:

Folder                                  
    Subfolder01                             
    Subfolder02                             
        Subfolder02.01                          
            Subfolder02.01.01                                       
                Subfolder02.01.01.01                                
            Subfolder02.01.02                                       
    Subfolder03                             
    Subfolder04                                     
        Subfolder04.01                              
            Subfolder04.01.01                                       
                Subfolder04.01.01.01                                
            Subfolder04.01.02                       
                Subfolder04.01.02.01                            
        Subfolder04.02                              

以下是我使用Apache POI库读取excel文件的方法:

public class ExcelReadClass {

    private static final String FILE_NAME = "D:/Work-Space/TESTExcel.xlsx";

    public void readExcel(String fileName) {

        try {

            // XSSFWorkbook  = XML SpreadSheet Format
            // is for Excel 2007 or above  


            Workbook workbook = new XSSFWorkbook(fileName); 

            // Accessing the particular sheet
            // here the parameter indicates the sheet number. 0 means first sheet, 1 means the second and so on
            /// accessing first sheet - which is " Components " 
            Sheet sheet = workbook.getSheetAt(0);

            /*
             * Sheet can also be accessed using the sheet name like shown below
             * Sheet sheet = workbook.getSheet("Components");
             */

            // geting the rows

            // following code will work with empty cells
            Row row = null;
            Cell cell = null;

            // Returns: the number of physically defined rows in the selected sheet
            //int noOfRows = sheet.getPhysicalNumberOfRows();

            //Returns: last row contained n this sheet (0-based)
            int noOfRows = sheet.getLastRowNum();

            // starting from  0 - which is the first row
            for(int i = 2; i <= noOfRows; i++) {

                row = sheet.getRow(i);

                //int noOfCells = row.getPhysicalNumberOfCells(); // returns the total number of cells in the selected row
                //int noOfCells = row.getLastCellNum(); // returns the number of the last cell in the row
                int noOfCells = 11;

这里我用Sysout输出文件结构 我必须将整个结构存储到数组中的地方

                // starting from 0 - which is the first column ( aka cell )
                for(int j = 1; j < noOfCells; j++) {

                    cell = row.getCell(j) ; // if there's no more cells, it returns null


                    if(cell != null ) {
                        System.out.print(getCellValue(cell) + "\t");
                    } else {
                        Cell blanckCell = row.createCell(j);
                        blanckCell.setCellValue("");
                        System.out.print(getCellValue(blanckCell) + "\t");
                    }
                }
                System.out.println();
            }

            workbook.close();

        } catch (FileNotFoundException e) {

            System.out.println("File is not available.");
            e.printStackTrace();

        } catch (IOException e) {

            System.out.println("Problem reading file from directory.");
            e.printStackTrace();

        } catch (NullPointerException e){

            System.err.println("Last part of Excel");
            e.printStackTrace();

        }


    }

    public Object getCellValue(Cell cell){
        Object cellValue = null;
        if(cell.getCellTypeEnum() == CellType.STRING){
            cellValue = cell.getStringCellValue();
        }else if(cell.getCellTypeEnum() == CellType.NUMERIC){
            cellValue = cell.getNumericCellValue();
        }else if(cell.getCellTypeEnum() == CellType.BOOLEAN){
            cellValue = cell.getBooleanCellValue();
        }else if(cell.getCellTypeEnum() == CellType.BLANK){
            cellValue = "";
        }
        return cellValue;
    }

}

2 个答案:

答案 0 :(得分:1)

在Java中,您可以将HashMap或TreeMap数据结构与ArrayList结合使用,并按如下方式对需求进行建模。

Map<String, Map<String, List<String>>>map = new HashMap<String, Map<String, List<String>>>();

然后,当您阅读文件夹的名称时,您可以将它们添加到我建议的数据结构中。 hashmap是您的文件夹。 hashmap映射的第一级键将包含“Subfolder01,Subfolder02,Subfolder03,Subfolder04”。相应的值将是已提到的文件夹中包含的文件夹。 这些值中的每一个都是Map<String, List<String>>mi,而<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css" integrity="sha384-BVYiiSIFeK1dGmJRAkycuHAHRg32OmUcww7on3RYdg4Va+PmSTsz/K68vbdEjh4u" crossorigin="anonymous"> <li itemscope="itemscope" itemtype="https://www.schema.org/SiteNavigationElement" id="menu-item-29" class="menu-item menu-item-type-post_type menu-item-object-page menu-item-has-children menu-item-29 dropdown"><a title="Therapieën" href="#" data-toggle="dropdown" class="dropdown-toggle" aria-haspopup="true">Therapieën <span class="caret"></span></a> <ul role="menu" class=" dropdown-menu"> <li itemscope="itemscope" itemtype="https://www.schema.org/SiteNavigationElement" id="menu-item-86" class="menu-item menu-item-type-post_type menu-item-object-page menu-item-86"><a title="Logopedie" href="http://localhost:81/wordpress/logopedie/">Logopedie</a></li> <li itemscope="itemscope" itemtype="https://www.schema.org/SiteNavigationElement" id="menu-item-85" class="menu-item menu-item-type-post_type menu-item-object-page menu-item-85"><a title="Bijlessen" href="http://localhost:81/wordpress/bijlessen/">Bijlessen</a></li> <li itemscope="itemscope" itemtype="https://www.schema.org/SiteNavigationElement" id="menu-item-84" class="menu-item menu-item-type-post_type menu-item-object-page menu-item-84"><a title="Audiologie" href="http://localhost:81/wordpress/audiologie/">Audiologie</a></li> <li itemscope="itemscope" itemtype="https://www.schema.org/SiteNavigationElement" id="menu-item-83" class="menu-item menu-item-type-post_type menu-item-object-page menu-item-83"><a title="Stemtherapie" href="http://localhost:81/wordpress/stemtherapie/">Stemtherapie</a></li> <li itemscope="itemscope" itemtype="https://www.schema.org/SiteNavigationElement" id="menu-item-82" class="menu-item menu-item-type-post_type menu-item-object-page menu-item-82"><a title="Verder ook begeleiding in" href="http://localhost:81/wordpress/verder-ook-begeleiding-in/">Verder ook begeleiding in</a></li> </ul> </li>又包含子文件夹“Subfolder02.01 ...”的名称,依此类推每个级别。 当您到达最后一级并找到最后一个文件夹中包含的文件时,您可以在ArrayList中插入这些名称。根据您所拥有的级别,您可以根据需要扩展或篡改数据结构的级别。

答案 1 :(得分:1)

这是一个帮助您启动的代码段

try {

            final String FILENAME = "c:\\Rest\\Test\\data.txt"; //change to your file location
            BufferedReader br = new BufferedReader(new InputStreamReader(
                    new FileInputStream(FILENAME), "UTF-8")); //change it to your reader
            String line;
            //read file line by line
            while ((line = br.readLine()) != null) {
                System.out.println(line);
                Node root = null;
                if (line == "Folder") {
                    root = new Node(null);
                } else {
                    String indexs = line.substring(9, line.length());
                    if (indexs.length() == 2) {
                        // insert to root
                    } else if (indexs.length() == 4) {
                        // create node and use readLine to all sub nodes
                    }
                }

            }
            br.close();
        } catch (IOException e) {
            e.printStackTrace();
        }

Node类:

import java.util.ArrayList;
import java.util.List;

public class Node {
    private String id;
    private final List<Node> children = new ArrayList<>();
    private final Node parent;

    public Node(Node parent) {
        this.parent = parent;
    }

    public String getId() {
        return id;
    }

    public void setId(String id) {
        this.id = id;
    }

    public List<Node> getChildren() {
        return children;
    }

    public Node getParent() {
        return parent;
    }

}