我的问题涉及QQmlComponent::create()创建的QObject
的有效期。 create()
返回的对象是QQmlComponent
的实例化,我将其添加到QML StackView
。我用C ++创建对象并将其传递给QML以显示在StackView
中。问题是当我从堆栈中弹出一个项目时出现错误。我写了一个演示应用来说明发生了什么。
免责声明:是的,我知道从C ++进入QML不是“最佳实践”。是的,我知道你应该在QML中做UI的东西。但是,在生产环境中,需要与UI共享大量的C ++代码,因此需要在C ++和CML之间进行一些互操作。我正在使用的主要机制是Q_PROPERTY
绑定,方法是在C ++端设置上下文。
此屏幕是演示开始时的样子:
StackView位于中心,背景为灰色,其中有一个项目(文本“默认视图”);此项目由QML实例化和管理。现在,如果按推送按钮,则C ++后端会从ViewA.qml
创建一个对象并将其放在堆栈中...这是一个显示以下内容的屏幕截图:
此时,我按弹出从StackView
删除“查看A”(上图中的红色)。 C ++调用QML从堆栈中弹出项目,然后删除它创建的对象。问题是QML需要这个对象用于过渡动画(我正在使用StackView
的默认动画),当我从C ++中删除它时它会抱怨。所以我想我明白为什么会这样,但我不知道如何找出QML完成对象的时间,以便我可以删除它。 如何确保使用我在C ++中创建的对象完成QML,以便我可以安全地删除它?
总结一下,以下是重现我所描述的问题的步骤:
以下输出显示了在上面的步骤3中弹出项目时发生的TypeError
:
在下面的输出中,我按“推”一次,然后按“弹出”。注意调用TypeError
时的两个~ViewA()
。
root object name = "appWindow"
[c++] pushView() called
qml: [qml] pushView called with QQuickRectangle(0xdf4c00, "my view")
[c++] popView() called
qml: [qml] popView called
[c++] deleting view
~ViewA() called
file:///opt/Qt5.8.0/5.8/gcc_64/qml/QtQuick/Controls/Private/StackViewSlideDelegate.qml:97: TypeError: Cannot read property 'width' of null
file:///opt/Qt5.8.0/5.8/gcc_64/qml/QtQuick/Controls/StackView.qml:899: TypeError: Type error
显然,正在发生的事情是StackView
正在使用的对象(项)正被C ++删除,但QML仍需要此项用于过渡动画。我想我可以在QML中创建对象并让QML引擎管理生命周期,但我需要设置对象的QQmlContext
以将QML视图绑定到C ++端的Q_PROPERTY
。 / p>
在Who owns object returned by QQmlIncubator上查看我的相关问题。
我已经生成了一个最简单的完整示例来说明问题。所有文件都列在下面。请特别注意~ViewA()
中的代码注释。
// main.qml
import QtQuick 2.3
import QtQuick.Controls 1.4
Item {
id: myItem
objectName: "appWindow"
signal signalPushView;
signal signalPopView;
visible: true
width: 400
height: 400
Button {
id: buttonPushView
text: "Push"
anchors.left: parent.left
anchors.top: parent.top
onClicked: signalPushView()
}
Button {
id: buttonPopView
text: "Pop"
anchors.left: buttonPushView.left
anchors.top: buttonPushView.bottom
onClicked: signalPopView()
}
Rectangle {
x: 100
y: 50
width: 250
height: width
border.width: 1
StackView {
id: stackView
initialItem: view
anchors.fill: parent
Component {
id: view
Rectangle {
color: "#DDDDDD"
Text {
anchors.centerIn: parent
text: "Default View"
}
}
}
}
}
function pushView(item) {
console.log("[qml] pushView called with " + item)
stackView.push(item)
}
function popView() {
console.log("[qml] popView called")
stackView.pop()
}
}
// ViewA.qml
import QtQuick 2.0
Rectangle {
id: myView
objectName: "my view"
color: "#FF4a4a"
Text {
text: "View A"
anchors.centerIn: parent
}
}
// viewa.h
#include <QObject>
class QQmlContext;
class QQmlEngine;
class QObject;
class ViewA : public QObject
{
Q_OBJECT
public:
explicit ViewA(QQmlEngine* engine, QQmlContext* context, QObject *parent = 0);
virtual ~ViewA();
// imagine that this view has property bindings used by 'context'
// Q_PROPERTY(type name READ name WRITE setName NOTIFY nameChanged)
QQmlContext* context = nullptr;
QObject* object = nullptr;
};
// viewa.cpp
#include "viewa.h"
#include <QQmlEngine>
#include <QQmlContext>
#include <QQmlComponent>
#include <QDebug>
ViewA::ViewA(QQmlEngine* engine, QQmlContext *context, QObject *parent) :
QObject(parent),
context(context)
{
// make property bindings visible to created component
this->context->setContextProperty("ViewAContext", this);
QQmlComponent component(engine, QUrl(QLatin1String("qrc:/ViewA.qml")));
object = component.create(context);
}
ViewA::~ViewA()
{
qDebug() << "~ViewA() called";
// Deleting 'object' in this destructor causes errors
// because it is an instance of a QML component that is
// being used in a transition. Deleting it here causes a
// TypeError in both StackViewSlideDelegate.qml and
// StackView.qml. If 'object' is not deleted here, then
// no TypeError happens, but then 'object' is leaked.
// How should 'object' be safely deleted?
delete object; // <--- this line causes errors
delete context;
}
// viewmanager.h
#include <QObject>
class ViewA;
class QQuickItem;
class QQmlEngine;
class ViewManager : public QObject
{
Q_OBJECT
public:
explicit ViewManager(QQmlEngine* engine, QObject* topLevelView, QObject *parent = 0);
QList<ViewA*> listOfViews;
QQmlEngine* engine;
QObject* topLevelView;
public slots:
void pushView();
void popView();
};
// viewmanager.cpp
#include "viewmanager.h"
#include "viewa.h"
#include <QQmlEngine>
#include <QQmlContext>
#include <QDebug>
#include <QMetaMethod>
ViewManager::ViewManager(QQmlEngine* engine, QObject* topLevelView, QObject *parent) :
QObject(parent),
engine(engine),
topLevelView(topLevelView)
{
QObject::connect(topLevelView, SIGNAL(signalPushView()), this, SLOT(pushView()));
QObject::connect(topLevelView, SIGNAL(signalPopView()), this, SLOT(popView()));
}
void ViewManager::pushView()
{
qDebug() << "[c++] pushView() called";
// create child context
QQmlContext* context = new QQmlContext(engine->rootContext());
auto view = new ViewA(engine, context);
listOfViews.append(view);
QMetaObject::invokeMethod(topLevelView, "pushView",
Q_ARG(QVariant, QVariant::fromValue(view->object)));
}
void ViewManager::popView()
{
qDebug() << "[c++] popView() called";
if (listOfViews.count() <= 0) {
qDebug() << "[c++] popView(): no views are on the stack.";
return;
}
QMetaObject::invokeMethod(topLevelView, "popView");
qDebug() << "[c++] deleting view";
auto view = listOfViews.takeLast();
delete view;
}
// main.cpp
#include <QGuiApplication>
#include <QQmlApplicationEngine>
#include <QQmlContext>
#include <QQuickView>
#include <QQuickItem>
#include "viewmanager.h"
#include <QDebug>
int main(int argc, char *argv[])
{
QGuiApplication app(argc, argv);
QQuickView view;
view.setSource(QUrl(QLatin1String("qrc:/main.qml")));
QObject* item = view.rootObject();
qDebug() << "root object name = " << item->objectName();
ViewManager viewManager(view.engine(), item);
view.show();
return app.exec();
}
答案 0 :(得分:1)
我发布了自己问题的答案。如果您发布答案,我会考虑接受您的答案,而不是这个答案。但是,这是一种可能的解决方法。
问题在于,用C ++创建的QML对象需要足够长的时间才能使QML引擎完成所有转换。我使用的技巧是将QML对象实例标记为删除,等待几秒钟让QML完成动画,然后删除该对象。 &#34; hacky&#34;这里的一部分是我必须猜测我应该等待多少秒,直到我认为QML完全与对象完成。
首先,我列出了计划销毁的对象。我还制作了一个插槽,在实际删除对象的延迟后调用:
class ViewManager : public QObject {
public:
...
QList<ViewA*> garbageBin;
public slots:
void deleteAfterDelay();
}
然后,当弹出堆栈项目时,我将项目添加到garbageBin
并在2秒内执行单次拍摄信号:
void ViewManager::popView()
{
if (listOfViews.count() <= 0) {
qDebug() << "[c++] popView(): no views are on the stack.";
return;
}
QMetaObject::invokeMethod(topLevelView, "popView");
// schedule the object for deletion in a few seconds
garbageBin.append(listOfViews.takeLast());
QTimer::singleShot(2000, this, SLOT(deleteAfterDelay()));
}
几秒钟后,调用deleteAfterDelay()
个插槽,&#34;垃圾收集&#34;该项目:
void ViewManager::deleteAfterDelay()
{
if (garbageBin.count() > 0) {
auto view = garbageBin.takeFirst();
qDebug() << "[c++] delayed delete activated for " << view->objectName();
delete view;
}
}
除了没有100%确信等待2秒总是足够长的时候,它似乎在实践中工作得非常好 - 不再有TypeError
s并且C ++创建的所有对象都被正确清理。< / p>
答案 1 :(得分:1)
我相信我已经找到了一种摆脱@Matthew Kraus建议的垃圾清单的方法。当弹出StackView时,我让QML处理破坏视图。
警告:代码段不完整,仅用于说明对OP帖子的扩展
function pushView(item, id) {
// Attach option to automate the destruction on pop (called by C++)
rootStackView.push(item, {}, {"destroyOnPop": true})
}
function popView(id) {
// Pop immediately (removes transition effects) and verify that the view
// was deleted (null). Else, delete immediately.
var old = rootStackView.pop({"item": null, "immediate": true})
if (old !== null) {
old.destroy() // Requires C++ assigns QML ownership
}
// Tracking views in m_activeList by id. Notify C++ ViewManager that QML has
// done his job
viewManager.onViewClosed(id)
}
如果该对象是C ++创建的,并且仍然归其所有,则您很快会发现解释器在删除时对您大吼大叫。
m_pEngine->setObjectOwnership(view, QQmlEngine::JavaScriptOwnership);
QVariant arg = QVariant::fromValue(view);
bool ret = QMetaObject::invokeMethod(
m_pRootPageObj,
"pushView",
Q_ARG(QVariant, arg),
Q_ARG(QVariant, m_idCnt));