我有一个类似下面提到的文档结构
{
"_id" : ObjectId("asdasdasdasdasdas"),
"info" : [
{
"dateTime" : ISODate("2016-08-19T12:10:16.000Z"),
"srcName" : null,
"parseFlag" : true,
"GrId" : null,
"eventMessage" : "Error1. "
},
{
"dateTime" : ISODate("2016-09-19T12:10:16.000Z"),
"srcName" : null,
"parseFlag" : false,
"GrId" : null,
"eventMessage" : "Error2"
},
{
"dateTime" : ISODate("2016-10-19T12:10:16.000Z"),
"srcName" : null,
"parseFlag" : false,
"GrId" : null,
"eventMessage" : "Error2"
},
],
"domain" : "asdasdas",
"fileName" : "sdasdsdfsd.dsf.gz",
"eventGroup" : "fault",
"eventId" : 62,
"type" : "1"
}
我必须根据信息中的日期时间过滤记录。例如,如果我必须单独获得八月份数据我该怎么做?
输出应该类似
{
"_id" : ObjectId("asdasdasdasdasdas"),
"info" : [
{
"dateTime" : ISODate("2016-08-19T12:10:16.000Z"),
"srcName" : null,
"parseFlag" : true,
"GrId" : null,
"eventMessage" : "Error1. "
},
"domain" : "asdasdas",
"fileName" : "sdasdsdfsd.dsf.gz",
"eventGroup" : "fault",
"eventId" : 62,
"type" : "1"
}
使用聚合和展开会花费大量时间。 让我知道如何处理这种情况