有没有办法让PopupMenu的项目水平对齐而不是垂直对齐?
我希望向窗口小部件添加更多行为并将其传递,因为PopupMenu的子窗口提供除渲染之外的所有要求。
答案 0 :(得分:3)
Flutter的popup menu有很多内部常量,它要求弹出窗口的轴是垂直的。如果要更改轴并完全控制布局和大小,可以复制该文件并开始编辑。
如果您对布局不太挑剔,可以通过将Row
窗口小部件作为单个弹出菜单项嵌入来伪造它。这里有一些代码证明了这种方法:
import 'package:flutter/material.dart';
void main() {
runApp(new MyApp());
}
class MyApp extends StatelessWidget {
@override
Widget build(BuildContext context) {
return new MaterialApp(
title: 'Flutter Demo',
home: new MyHomePage(),
);
}
}
/// An arbitrary widget that lives in a popup menu
class PopupMenuWidget<T> extends PopupMenuEntry<T> {
const PopupMenuWidget({ Key key, this.height, this.child }) : super(key: key);
@override
final Widget child;
@override
final double height;
@override
bool get enabled => false;
@override
_PopupMenuWidgetState createState() => new _PopupMenuWidgetState();
}
class _PopupMenuWidgetState extends State<PopupMenuWidget> {
@override
Widget build(BuildContext context) => widget.child;
}
class MyHomePage extends StatelessWidget {
MyHomePage({Key key}) : super(key: key);
@override
Widget build(BuildContext context) {
return new Scaffold(
appBar: new AppBar(
actions: <Widget>[
new PopupMenuButton<String>(
onSelected: (String value) {
print("You selected $value");
},
itemBuilder: (BuildContext context) {
return [
new PopupMenuWidget(
height: 40.0,
child: new Row(
children: [
new IconButton(
icon: new Icon(Icons.add),
onPressed: () => Navigator.pop(context, 'add')),
new IconButton(
icon: new Icon(Icons.remove),
onPressed: () => Navigator.pop(context, 'remove')),
],
),
),
];
}
),
],
),
);
}
}