这是所需的输出。包含2行的CSV文件：
1639, 06/05/17, 08,09,16,26,37,50
1639, 06/05/17, 13,28,32,33,37,38
今天，我只有这个，但使用VBA Excel代码来清理/整理数据：
08,09,16,26,37,50
13,28,32,33,37,38
在第一行'1639，06/05/17'来自Resultado <span>Concurso 1639 (06/05/2017)</span>和'08,09,16,26,37,50'来自下面提供的标签：
<ul class="numbers dupla-sena">
<h6>1º sorteio</ <h6>1º sorteio</h6>
<li>08</li><li>09</li><li>16</li><li>26</li><li>37</li><li>50</li>
</ul>
在第二行，我们可能会从第1行复制'1639,06 / 05/17'而'13,28,32,33,37,38'来自另一个标签：
<ul class="numbers dupla-sena">
<h6>2º sorteio</h6>
<li>13</li><li>28</li><li>32</li><li>33</li><li>37</li><li>38</li>
</ul>
以下是我的代码：
import requests
from bs4 import BeautifulSoup as soup
url = 'http://loterias.caixa.gov.br/wps/portal/loterias/landing/duplasena/'
r = requests.get(url)
ltr = soup(r.text, "xml")
ltr.findAll("div",{"class":"content-section section-text with-box no-margin-bottom"})
filename = "ds_1640.csv"
f=open(filename,"w")
使用下面的命令，我想我可以得到我想要的所有内容，但我不知道如何以我需要的方式提取数据：
ltr.findAll("div",{"class":"content-section section-text with-box no-margin-bottom"})
所以，我尝试了另一种方法来捕捉'1ºsorteioda dupla-sena'中的值
print('-----------------dupla-sena 1º sorteio-----------------------------')
d1 = ltr.findAll("ul",{"class":"numbers dupla-sena"})[0].text.strip()
print(ltr.findAll("ul",{"class":"numbers dupla-sena"})[0].text.strip())
输出1
1º sorteio
080916263750
分开两位数字
d1 = '0'+ d1 if len(d1)%2 else d1
gi = [iter(d1)]*2
r = [''.join(dz1) for dz1 in zip(*gi)]
d3=",".join(r)
结果
08,09,16,26,37,50
第二次提取也是如此
print('-----------------dupla-sena 2º sorteio-----------------------------')
dd1 = ltr.findAll("ul",{"class":"numbers dupla-sena"})[1].text.strip()
print(ltr.findAll("ul",{"class":"numbers dupla-sena"})[1].text.strip())
输出2
2º sorteio
132832333738
分开两位数字
dd1 = '0'+ dd1 if len(dd1)%2 else dd1
gi = [iter(dd1)]*2
r1 = [''.join(ddz1) for ddz1 in zip(*gi)]
dd3=",".join(r1)
然后我们
13,28,32,33,37,38
将数据保存到csv文件
f.write(d3 + ',' + dd3 +'\n')
f.close()
输出：当前目录中的csv文件：
01,º ,so,rt,ei,o
,08,09,16,26,37,50,02,º ,so,rt,ei,o
,13,28,32,33,37,38
我可以使用上面的方法/输出，但我必须使用VBA excel来处理这个混乱的数据，但我试图避免使用vba代码。 Actualy我对学习Python更感兴趣并且使用越来越多这个功能强大的工具。 通过这个解决方案，我只实现了我想要的一个部分，即：
08,09,16,26,37,50
13,28,32,33,37,38
但是，正如我们所知，所需的输出是：
1639, 06/05/17, 08,09,16,26,37,50
1639, 06/05/17, 13,28,32,33,37,38
我在MAC OS X Yosemite（10.10.5）中使用Python 3.6.1（v3.6.1 :)，Jupyter笔记本。
我怎样才能实现这一目标？我不知道如何提取'1639,06 / 05/17'并将其放入csv文件中，是否有更好的方法来提取六个数字（08,09,16,26,37,50和13 ，28,32,33,37,38）并且不使用下面的代码而不使用vba？
分隔两位数字：
d1 = '0'+ d1 if len(d1)%2 else d1
gi = [iter(d1)]*2
r = [''.join(dz1) for dz1 in zip(*gi)]
import requests
from bs4 import BeautifulSoup
import re
import csv
url = 'http://loterias.caixa.gov.br/wps/portal/loterias/landing/duplasena/'
r = requests.get(url)
soup = BeautifulSoup(r.text, "lxml") ## "lxml" to avoid the warning
pat = re.compile(r'(?i)(?<=concurso)\s*(?P<concurso>\d+)\s*\((?P<data>.+?)(?=\))')
concurso_e_data = soup.find(id='resultados').h2.span.text
match = pat.search(concurso_e_data)
# first I would do the above part differently seeing as how you want the end data to look
if match:
concurso, data = match.groups()
nums = soup.find_all("ul", {"class": "numbers dupla-sena"})
num_headers = (','.join(['numero%d']*6) % tuple(range(1,7))).split(',')
# unpack numheaders into field names
field_names = ['sena', 'data', *num_headers]
# above gives you this
# field_names = [
# 'sena', ## I've changed "seria"for "sena"
# 'data',
# 'numero1',
# 'numero2',
# 'numero3',
# 'numero4',
# 'numero5',
# 'numero6',
# ]
rows = []
# then add the numbers
# nums is all the `ul` list elements contains the drawing numbers
for group in nums:
# start each row with the shared concurso, data elements
row = [concurso, data]
# for each `ul` get all the `li` elements containing the individual number
for num in group.findAll('li'):
# add each number
row.append(int(num.text))
# get [('sena', '1234'), ('data', '12/13'2017'),...]
row_title_value_pairs = zip(field_names, row)
# turn into dict {'sena': '1234', 'data': '12/13/2017', ...}
row_dict = dict(row_title_value_pairs)
rows.append(row_dict)
# so now rows looks like: [{
# 'sena': '1234',
# 'data': '12/13/2017',
# 'numero1': 1,
# 'numero2': 2,
# 'numero3': 3,
# 'numero4': 4,
# 'numero5': 5,
# 'numero6': 6
# }, ...]
with open('file_v5.csv', 'w', encoding='utf-8') as csvfile:
csv_writer = csv.DictWriter(
csvfile,
fieldnames=field_names,
dialect='excel',
extrasaction='ignore', # drop extra fields if not in field_names not necessary but just in case
quoting=csv.QUOTE_NONNUMERIC # quote anything thats not a number, again just in case
)
csv_writer.writeheader()
for row in rows:
csv_writer.writerow(row_dict)
输出
# "sena","data","numero1","numero2","numero3","numero4","numero5","numero6"
# "1641","11/05/2017",1,5,15,28,30,43
# "1641","11/05/2017",1,5,15,28,30,43 #This comes from 1. drawing and not
from the corcect one (2.)
import requests
from bs4 import BeautifulSoup
import re
import csv
url = 'http://loterias.caixa.gov.br/wps/portal/loterias/landing/duplasena/'
r = requests.get(url)
soup = BeautifulSoup(r.text, "lxml") ## "lxml" to avoid the warning
pat = re.compile(r'(?i)(?<=concurso)\s*(?P<concurso>\d+)\s*\((?P<data>.+?)(?=\))')
concurso_e_data = soup.find(id='resultados').h2.span.text
match = pat.search(concurso_e_data)
# everything should be indented under this block since
# if there is no match then none of the below code should run
if match:
concurso, data = match.groups()
nums = soup.find_all("ul", {"class": "numbers dupla-sena"})
num_headers = (','.join(['numero%d']*6) % tuple(range(1,7))).split(',')
field_names = ['sena', 'data', *num_headers]
# PROBLEM 1
# all this should be indented into the `if match:` block above
# none of this should run if there is no match
# you cannot build the rows without the match for sena and data
# Let's add some print statements to see whats going on
rows = []
for group in nums:
# here each group is a full `sena` row from the site
print('Pulling sena: ', group.text)
row = [concurso, data]
print('Adding concurso + data to row: ', row)
for num in group.findAll('li'):
row.append(int(num.text))
print('Adding {} to row.'.format(num))
print('Row complete: ', row)
row_title_value_pairs = zip(field_names, row)
print('Transform row to header, value pairs: ', row_title_value_pairs)
row_dict = dict(row_title_value_pairs)
print('Row dictionary: ', row_dict)
rows.append(row_dict)
print('Rows: ', rows)
# PROBLEM 2
# It would seem that you've confused this section when switching
# out the original list comprehension with the more explicit
# for loop in building the rows.
# The below block should be indented to this level.
# Still under the `if match:`, but out of the the
# `for group in nums:` above
# the below block loops over rows, but you are still building
# the rows in the for loop
# you are effectively double looping over the values in `row`
with open('ds_v4_copy5.csv', 'w', encoding='utf-8') as csvfile:
csv_writer = csv.DictWriter(
csvfile,
fieldnames=field_names,
dialect='excel',
extrasaction='ignore', # drop extra fields if not in field_names not necessary but just in case
quoting=csv.QUOTE_NONNUMERIC # quote anything thats not a number, again just in case
)
csv_writer.writeheader()
# this is where you are looping extra because this block is in the `for` loop mentioned in my above notes
#for row in rows: ### I tried here to avoid the looping extra
#print('Adding row to CSV: ', row)
csv_writer.writerow(row_dict)
我想我按照你的指示行事。但到目前为止我们得到了这个：
"sena","data","numero1","numero2","numero3","numero4","numero5","numero6"
"1643","16/05/2017",3,4,9,19,21,26 #which is "1º sorteio"
仍然缺少“2ºsorteio”。我知道我做错了什么，因为“1ºsorteio”和“2ºsorteio”都在：
print(rows[0]) --> {'sena': '1643', 'data': '16/05/2017', 'numero1': 1, 'numero2': 21, 'numero3': 22, 'numero4': 43, 'numero5': 47, 'numero6': 50}
print(rows[1]) --> {'sena': '1643', 'data': '16/05/2017', 'numero1': 3, 'numero2': 4, 'numero3': 9, 'numero4': 19, 'numero5': 21, 'numero6': 26}
但是，当我尝试将row_dict的内容存储在csv中时（row_dict中只显示row [0]。我正在试图弄清楚如何包含丢失的那个。也许我错了，但我认为row_dict中应该包含“1ºsorteio”和“2ºsorteio”，但是当我们看到这个时，代码不会确认它（这是猜测）：
print(row_dict)
{'sena': '1643', 'data': '16/05/2017', 'numero1': 3, 'numero2': 4, 'numero3': 9, 'numero4': 19, 'numero5': 21, 'numero6': 26}
我看不出我做错了什么。我知道这个答案花了很多时间，但我在这个过程中与你学到了很多东西。并且已经使用了我学习的几种工具（re，concepts，dict，zip）。
答案 0 :(得分：1)
免责声明：我不熟悉美丽的汤，我通常使用lxml，据说......
soup = BeautifulSoup(response.text) # <-- edit showing how i assigned soup
pat = re.compile(r'(?i)(?<=concurso)\s*(?P<concurso>\d+)\s*\((?P<data>.+?)(?=\))')
concurso_e_data = soup.find(id='resultados').h2.span.text
match = pat.search(concurso_e_data)
if match:
concurso, data = match.groups()
nums = soup.find_all("ul", {"class": "numbers dupla-sena"})
numeros = []
for i in nums:
numeros.append(','.join(j.text for j in i.findAll('li')))
rows = []
for n in numeros:
rows.append(','.join([concurso, data, n]))
print(rows)
['1639,06/05/2017,08,09,16,26,37,50', '1639,06/05/2017,13,28,32,33,37,38']
虽然这是您要求的格式，但是在数字组中使用逗号（列分隔符）并不是一个坏主意。您应该使用其他字符分隔或使用空格分隔数字。
在评论部分写作并不是最好的方法，所以...假设您真正想要的格式为8行，如下所示(seria, data, num1, num2, ... num6)其中seria和{{1}是字符串，数字是data s：
int这部分有点混乱：
# first I would do the above part differently seeing as how you want the end data to look
...
if match:
concurso, data = match.groups()
nums = soup.find_all("ul", {"class": "numbers dupla-sena"})
num_headers = (','.join(['numero%d']*6) % tuple(range(1,7))).split(',')
# unpack numheaders into field names
field_names = ['seria', 'data', *num_headers]
# above gives you this
# field_names = [
# 'seria',
# 'data',
# 'numero1',
# 'numero2',
# 'numero3',
# 'numero4',
# 'numero5',
# 'numero6',
# ]
rows = [
dict(zip(
field_names,
[concurso, data, *[int(num.text) for num in group.findAll('li')]]
))
for group in nums]
# so now rows looks like: [{
# 'seria': '1234',
# 'data': '12/13/2017',
# 'numero1': 1,
# 'numero2': 2,
# 'numero3': 3,
# 'numero4': 4,
# 'numero5': 5,
# 'numero6': 6
# }, ...]
with open('file.csv', 'a', encoding='utf-8') as csvfile:
csv_writer = csv.DictWriter(
csvfile,
fieldnames=field_names,
dialect='excel',
extrasaction='ignore', # drop extra fields if not in field_names not necessary but just in case
quoting=csv.QUOTE_NONNUMERIC # quote anything thats not a number, again just in case
)
csv_writer.writeheader()
for row in rows:
csv_writer.writerow(row_dict)
所以让我用另一种方式写下来：
rows = [
dict(zip(
field_names,
[concurso, data, *[int(num.text) for num in group.findAll('li')]
))
for group in nums]
我希望您从中学到的一件事是在学习时使用rows = []
# then add the numbers
# nums is all the `ul` list elements contains the drawing numbers
for group in nums:
# start each row with the shared concurso, data elements
row = [concurso, data]
# for each `ul` get all the `li` elements containing the individual number
for num in group.findAll('li'):
# add each number
row.append(int(num.text))
# get [('seria', '1234'), ('data', '12/13'2017'),...]
row_title_value_pairs = zip(field_names, row)
# turn into dict {'seria': '1234', 'data': '12/13/2017', ...}
row_dict = dict(row_title_value_pairs)
rows.append(row_dict)
# or just write the csv here instead of appending to rows and re-looping over the values
...
语句，这样您就可以理解代码的作用。我不会进行更正，但我会指出它们并在每个发生重大变化的位置添加print语句......
print运行此命令，查看打印语句显示的内容。但是也要阅读这些注释，因为如果sena，数据不匹配会导致错误。
提示：进行缩进，然后在最后的match = pat.search(concurso_e_data)
# everything should be indented under this block since
# if there is no match then none of the below code should run
if match:
concurso, data = match.groups()
nums = soup.find_all("ul", {"class": "numbers dupla-sena"})
num_headers = (','.join(['numero%d']*6) % tuple(range(1,7))).split(',')
field_names = ['sena', 'data', *num_headers]
# PROBLEM 1
# all this should be indented into the `if match:` block above
# none of this should run if there is no match
# you cannot build the rows without the match for sena and data
# Let's add some print statements to see whats going on
rows = []
for group in nums:
# here each group is a full `sena` row from the site
print('Pulling sena: ', group.text)
row = [concurso, data]
print('Adding concurso + data to row: ', row)
for num in group.findAll('li'):
row.append(int(num.text))
print('Adding {} to row.'.format(num))
print('Row complete: ', row)
row_title_value_pairs = zip(field_names, row)
print('Transform row to header, value pairs: ', row_title_value_pairs)
row_dict = dict(row_title_value_pairs)
print('Row dictionary: ', row_dict)
rows.append(row_dict)
print('Rows: ', rows)
# PROBLEM 2
# It would seem that you've confused this section when switching
# out the original list comprehension with the more explicit
# for loop in building the rows.
# The below block should be indented to this level.
# Still under the `if match:`, but out of the the
# `for group in nums:` above
# the below block loops over rows, but you are still building
# the rows in the for loop
# you are effectively double looping over the values in `row`
with open('file_v5.csv', 'w', encoding='utf-8') as csvfile:
csv_writer = csv.DictWriter(
csvfile,
fieldnames=field_names,
dialect='excel',
extrasaction='ignore', # drop extra fields if not in field_names not necessary but just in case
quoting=csv.QUOTE_NONNUMERIC # quote anything thats not a number, again just in case
)
csv_writer.writeheader()
# this is where you are looping extra because this block is in the `for` loop mentioned in my above notes
for row in rows:
print('Adding row to CSV: ', row)
csv_writer.writerow(row_dict)
块下添加else: print('No sena, data match!') ...但是首先运行它并检查它打印的内容。
答案 1 :(得分：0)
（代表OP发布）。
在你帮助@Verbal_Kint的帮助下，我们来到了这里！输出我需要的方式！我已将输出更改为：
sena;data;numero1;numero2;numero3;numero4;numero5;numero6
1644;18/05/2017;4;6;31;39;47;49
1644;18/05/2017;20;37;44;45;46;50
因此，他们关注“，”和“;”在Excel中，我决定更改","的{{1}}以在Excel中打开列而不会出现任何问题。
";"