Question

所以我有一个问题，如果我将代码中的“业务”部分保留在没有它的情况下表单不起作用，它就可以了！

    <div class="row control-group">
                            <div class="form-group col-xs-12 floating-label-form-group controls">
                                <label for="phone">Phone Number</label>
                                <input type="tel" class="form-control" placeholder="Phone Number" id="phone" required data-validation-required-message="Please enter your phone number.">
                                <p class="help-block text-danger"></p>
                            </div>
                        </div>
<!-- This part breaks the code -->
<div class="row control-group">
                            <div class="form-group col-xs-12 floating-label-form-group controls">
                                <label for="business">Promo Code</label>
                                <input type="text" class="form-control" placeholder="Promo Code" id="business" required data-validation-required-message="Please enter promo code here, if you don't have one enter 0.">
                                <p class="help-block text-danger"></p>
                            </div>
                        </div>
 <!-- If I remove this part it works -->

                        <div class="row control-group">
                            <div class="form-group col-xs-12 floating-label-form-group controls">
                                <label for="message">Message</label>
                                <textarea rows="5" class="form-control" placeholder="Message and Zip code goes here" id="message" required data-validation-required-message="Please enter a message."></textarea>
                                <p class="help-block text-danger"></p>
                            </div>
                        </div>

因此，如果我运行html代码而没有说“它打破了代码”的部分，并且在php端没有“业务”，它运行得很好，我收到了一封电子邮件。只是在启用该字段的情况下，我才收到电子邮件：/

PHP方面：

<?php
// stuff over here
if(empty($_POST['name'])        ||
   empty($_POST['email'])       ||
   empty($_POST['phone'])       || 
   empty($_POST['business'])   ||
   empty($_POST['message']) ||
   !filter_var($_POST['email'],FILTER_VALIDATE_EMAIL))
   {
    echo "No arguments Provided!";
    return false;
   }

$name = strip_tags(htmlspecialchars($_POST['name']));
$email_address = strip_tags(htmlspecialchars($_POST['email']));
$phone = strip_tags(htmlspecialchars($_POST['phone']));
$business = strip_tags(htmlspecialchars($_POST['business']));
$message = strip_tags(htmlspecialchars($_POST['message']));

// here goes the email part
$to = 'email@yahoo.com'; 
$email_subject = "Website Contact Form:  $name";
$email_body = "You have received a new message from your website contact form.\n\n"."Here are the details:\n\nName: $name\n\nEmail: $email_address\n\nPhone: $phone\n\nBusiness: $business\n\nMessage:\n$message";
$headers = "From: noreply@site.com"; // This is the email address the generated message will be from. We recommend using something like noreply@yourdomain.com.
$headers .= "Reply-To: $email_address"; 
mail($to,$email_subject,$email_body,$headers);
return true;            
?>

非常感谢任何帮助，提前谢谢！

部分PHP表单不起作用

0 个答案: