Question

我尝试将两列中的值相加并按日截断我的日期字段。我构建了SQL查询来执行此操作（可行）：

SELECT date_trunc('day', date) AS Day, SUM(fremont_bridge_nb) AS 
Sum_NB, SUM(fremont_bridge_sb) AS Sum_SB FROM bike_count GROUP BY Day 
ORDER BY Day;

但是当我尝试将其格式化为peewee时，我会遇到问题：

Bike_Count.select(fn.date_trunc('day', Bike_Count.date).alias('Day'),
fn.SUM(Bike_Count.fremont_bridge_nb).alias('Sum_NB'),
fn.SUM(Bike_Count.fremont_bridge_sb).alias('Sum_SB'))
.group_by('Day').order_by('Day')

我没有收到任何错误，但是当我打印出我存储的变量时，它会显示：

 <class 'models.Bike_Count'> SELECT date_trunc(%s, "t1"."date") AS 
Day, SUM("t1"."fremont_bridge_nb") AS Sum_NB, 
SUM("t1"."fremont_bridge_sb") AS Sum_SB FROM "bike_count" AS t1 ORDER 
BY %s ['day', 'Day']

我用Python编写的唯一成功获取数据的是：

 Bike_Count.get(Bike_Count.id == 1).date

Answer 1

如果您只是按顺序将一个字符串粘贴到您的组中，Peewee将尝试将其作为值进行参数化。这是为了避免SQL注入haxx。

要解决此问题，您可以在SQL('Day')和'Day'来电中使用group_by()代替order_by()。

另一种方法是将函数调用粘贴到GROUP BY和ORDER BY中。以下是您将如何做到这一点：

day = fn.date_trunc('day', Bike_Count.date)
nb_sum = fn.SUM(Bike_Count.fremont_bridge_nb)
sb_sum = fn.SUM(Bike_Count.fremont_bridge_sb)

query = (Bike_Count
         .select(day.alias('Day'), nb_sum.alias('Sum_NB'), sb_sum.alias('Sum_SB'))
         .group_by(day)
         .order_by(day))

或者，如果您愿意：

query = (Bike_Count
         .select(day.alias('Day'), nb_sum.alias('Sum_NB'), sb_sum.alias('Sum_SB'))
         .group_by(SQL('Day'))
         .order_by(SQL('Day')))

peewee select（）返回SQL查询，而不是实际数据

1 个答案: