拆分地址字段

Question

我有一个地址栏，其中包含街道地址以及邮政信箱号码。我想将街道地址和邮政编码提取到一个单独的栏目中，我该怎么做？

样本数据

     1 ABC CDE PO BOX 650
       15 N. MAIN STREET P.O. BOX 009
       (ABC)PO BOX 5909 
        1 TAKEWAY PLAZA          
       PO BOX 146012  Parkway STREET

  

期望的输出： -

STREET ADDRESS               ADDRESS2


  1 ABC CDE                    P.O. BOX 650
  15 N. MAIN STREET            P.O. BOX 009
  ABC                          P.O. BOX 5909
  1 TAKEWAY PLAZA
  Parkway STREET               P.O. BOX 146012

Answer 1

解析地址可能是一个滑坡。也就是说，你好像是在关注邮政信箱，所以这会让它更容易管理，

也就是说，您可以考虑使用GOOGLE API来规范您的地址Address standardization within a database

这将通过标准化和清洁字符串来产生所需的结果。然后解析字符串，然后通过XML和Stuff（）重构它。

有许多可用的解析/拆分功能，我确实在下面提供了

示例

Declare @YourTable table (address varchar(250))
Insert Into @YourTable values
('1 ABC CDE PO BOX 650'),
('15 N. MAIN STREET P.O. BOX 009'),
('(ABC)PO BOX 5909'),
('1 TAKEWAY PLAZA'),          
('PO BOX 146012  Parkway STREET')

Select A.*
      ,C.*
 From  @YourTable A
 Cross Apply (
               Select CleanString = replace(replace(replace(replace(replace(replace(replace(A.Address,'  ',' '),'P. O','P.O'),'P.','P'),'O. ','O'),'O BOX','OBOX'),'BOX ','BOX'),'POBOX',' POBOX')+' '
             ) B
 Outer Apply (
                Select Address1 = Stuff((Select ' ' +RetVal 
                                         From  [dbo].[udf-Str-Parse](B.CleanString,' ')
                                         Where RetVal Not Like 'POBOX%'
                                         For XML Path ('')),1,1,'')
                      ,Address2 = (Select replace(RetVal,'POBOX','P.O. Box ') From  [dbo].[udf-Str-Parse](B.CleanString,' ') Where RetVal Like 'POBOX%')
             ) C

<强>返回

address                         Address1            Address2
1 ABC CDE PO BOX 650            1 ABC CDE           P.O. Box 650
15 N. MAIN STREET P.O. BOX 009  15 N. MAIN STREET   P.O. Box 009
(ABC)PO BOX 5909                (ABC)               P.O. Box 5909
1 TAKEWAY PLAZA                 1 TAKEWAY PLAZA     NULL
PO BOX 146012  Parkway STREET   Parkway STREET      P.O. Box 146012

感兴趣的UDF

CREATE FUNCTION [dbo].[udf-Str-Parse] (@String varchar(max),@Delimiter varchar(10))
Returns Table 
As
Return (  
    Select RetSeq = Row_Number() over (Order By (Select null))
          ,RetVal = LTrim(RTrim(B.i.value('(./text())[1]', 'varchar(max)')))
    From  (Select x = Cast('<x>' + replace((Select replace(@String,@Delimiter,'§§Split§§') as [*] For XML Path('')),'§§Split§§','</x><x>')+'</x>' as xml).query('.')) as A 
    Cross Apply x.nodes('x') AS B(i)
);
--Thanks Shnugo for making this XML safe
--Select * from [dbo].[udf-Str-Parse]('Dog,Cat,House,Car',',')
--Select * from [dbo].[udf-Str-Parse]('John Cappelletti was here',' ')
--Select * from [dbo].[udf-Str-Parse]('this,is,<test>,for,< & >',',')