Question

我正在尝试内部连接来自OS TICKET数据库的3个表。

我使用的代码是$qry = "SELECT qbcd_user_email.address, qbcd_user_email.user_id FROM qbcd_user_email INNER JOIN qbcd_user ON qbcd_user.id = qbcd_user_email.user_id INNER JOIN qbcd_ticket ON qbcd_ticket.user_id WHERE (qbcd_user_email.address = '.$email.') ORDER BY qbcd_ticket.ticket_id DESC";

代码正在返回：

string(287) "SELECT qbcd_user_email.address, qbcd_user_email.user_id FROM qbcd_user_email INNER JOIN qbcd_user ON qbcd_user.id = qbcd_user_email.user_id INNER JOIN qbcd_ticket ON qbcd_ticket.user_id WHERE (qbcd_user_email.address = '.patrick.kershner@gmail.com.') ORDER BY qbcd_ticket.ticket_id DESC"

但它没有在while子句中显示任何内容：

while ($row = mysqli_fetch_assoc($result)){
echo $row['qbcd_ticket.number]."<br>";}

我不确定发生了什么，或者为什么它没有显示结果。

有人可以查看我上面的代码并验证吗？

Answer 1

尝试将数字添加到所选属性

$qry = "SELECT qbcd_user_email.address, qbcd_user_email.user_id, qbcd_ticket.number FROM qbcd_user_email INNER JOIN qbcd_user ON qbcd_user.id = qbcd_user_email.user_id INNER JOIN  qbcd_ticket ON qbcd_ticket.user_id WHERE (qbcd_user_email.address = '.$email.') ORDER BY qbcd_ticket.ticket_id DESC"

Answer 2

第一个表是：

qbcd_ticket:
rows:

ticket_id | number | user_id | user_email_id | status_id | dept_id | and more...
5     |  762086|   2     |      0    |      1|  1  |    


the next is qbcd_user_email
rows:
id | user_id | flags | address
2  |    2    |  0    |  example@demo.com

the last is: qbcd_user
id | org_id | default_email_id | status | name              | created             | updated 
2  |    0   |   2          |     0  |  Patrick Kershner | 2017-03-03 10:44:28 | 2017-03-03 10:44:28

我需要显示的信息是与客户关联的所有相应的门票，其中=电子邮件地址。

唯一不会更改的静态变量是$_SESSION['user_email'];，它通过登录成员区域来记录。

不显示内部连接3表的结果

2 个答案: